matplotlib-users

[Matplotlib-users] color xy plot

[sordnay <so...@gm...>]

Hi all,
I'm trying to plot in 2D, 3 variables from time series, instead of volume I
want color for the third variable.
I have partial success with a scatter plot, but I'm unable to manage the
colorbar so it represents z values,
I needed to sort the variables and it's getting a bit ugly, so I though I
might be missing some other function ?
this is what I used:
            pylab.figure()
            x=self.stData[items[0]]
            y=self.stData[items[1]]
            z=self.stData[items[2]]
            points=zip(x,y)
            points3=sorted(zip(z,points))
            for i,p in enumerate(points3):
                z[i]=p[0]
                x[i]=p[1][0]
                y[i]=p[1][1]
            #colors=pylab.linspace(z.min(),z.max(),len(z)) did not work
            colors=pylab.linspace(0,1,len(z))
            pylab.scatter(x,y,c=colors,faceted=False)
            pylab.colorbar()
            pylab.show()
but even if I could get the colorbar ticks to represent z values, in fact
this is not correct as this gives every point "one" color, and this is not
correct...
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Re: [Matplotlib-users] color xy plot

[John H. <jd...@gm...>]

On Fri, Jun 20, 2008 at 6:14 PM, sordnay <so...@gm...> wrote:
>
> Hi all,
> I'm trying to plot in 2D, 3 variables from time series, instead of volume I
> want color for the third variable.
> I have partial success with a scatter plot, but I'm unable to manage the
> colorbar so it represents z values,
> I needed to sort the variables and it's getting a bit ugly, so I though I
> might be missing some other function ?
> this is what I used:
>            pylab.figure()
>            x=self.stData.[items[0]]
>            y=self.stData.[items[1]]
>            z=self.stData.[items[2]]
>            points=zip(x,y)
>            points3=sorted(zip(z,points))
>            for i,p in enumerate(points3):
>                z[i]=p[0]
>                x[i]=p[1][0]
>                y[i]=p[1][1]
>            #colors=pylab.linspace(z.min(),z.max(),len(z)) did not work
>            colors=pylab.linspace(0,1,len(z))
>            pylab.scatter(x,y,c=colors,faceted=False)

Just pass c=z to scatter if z are the values you want to colormap.

JDH

Re: [Matplotlib-users] color xy plot

[sordnay <so...@gm...>]

John Hunter-4 wrote:
> 
> On Fri, Jun 20, 2008 at 6:14 PM, sordnay <so...@gm...> wrote:
>>
>> Hi all,
>> I'm trying to plot in 2D, 3 variables from time series, instead of volume
>> I
>> want color for the third variable.
>> I have partial success with a scatter plot, but I'm unable to manage the
>> colorbar so it represents z values,
>> I needed to sort the variables and it's getting a bit ugly, so I though I
>> might be missing some other function ?
>> this is what I used:
>>            pylab.figure()
>>            x=self.stData.[items[0]]
>>            y=self.stData.[items[1]]
>>            z=self.stData.[items[2]]
>>            points=zip(x,y)
>>            points3=sorted(zip(z,points))
>>            for i,p in enumerate(points3):
>>                z[i]=p[0]
>>                x[i]=p[1][0]
>>                y[i]=p[1][1]
>>            #colors=pylab.linspace(z.min(),z.max(),len(z)) did not work
>>            colors=pylab.linspace(0,1,len(z))
>>            pylab.scatter(x,y,c=colors,faceted=False)
> 
> Just pass c=z to scatter if z are the values you want to colormap.
> 
> JDH
> 
> -------------------------------------------------------------------------
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> 
> 

yes it was lot easier, but i had to set the vmin and vmax kwargs or it
wouldn't work:
            sigbrowse=figure()
            x=self.stData.Data[items[0]]
            y=self.stData.Data[items[1]]
            z=self.stData.Data[items[2]]
            scatter(x,y,c=z,faceted=False,vmin=z.min(),vmax=z.max())
            colorbar()
            show()

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Re: [Matplotlib-users] color xy plot

[John [H2O] <was...@gm...>]

Bringing up an old thread, but just curious if this can be done with the plot
command as well, as in:
plt.plot(X,Y[1:3,:].T,c=['blue','red'])

Thanks,
john


sordnay wrote:
> 
> 
> John Hunter-4 wrote:
>> 
>> On Fri, Jun 20, 2008 at 6:14 PM, sordnay <so...@gm...> wrote:
>>>
>>> Hi all,
>>> I'm trying to plot in 2D, 3 variables from time series, instead of
>>> volume I
>>> want color for the third variable.
>>> I have partial success with a scatter plot, but I'm unable to manage the
>>> colorbar so it represents z values,
>>> I needed to sort the variables and it's getting a bit ugly, so I though
>>> I
>>> might be missing some other function ?
>>> this is what I used:
>>>            pylab.figure()
>>>            x=self.stData.[items[0]]
>>>            y=self.stData.[items[1]]
>>>            z=self.stData.[items[2]]
>>>            points=zip(x,y)
>>>            points3=sorted(zip(z,points))
>>>            for i,p in enumerate(points3):
>>>                z[i]=p[0]
>>>                x[i]=p[1][0]
>>>                y[i]=p[1][1]
>>>            #colors=pylab.linspace(z.min(),z.max(),len(z)) did not work
>>>            colors=pylab.linspace(0,1,len(z))
>>>            pylab.scatter(x,y,c=colors,faceted=False)
>> 
>> Just pass c=z to scatter if z are the values you want to colormap.
>> 
>> JDH
>> 
>> -------------------------------------------------------------------------
>> Check out the new SourceForge.net Marketplace.
>> It's the best place to buy or sell services for
>> just about anything Open Source.
>> http://sourceforge.net/services/buy/index.php
>> _______________________________________________
>> Matplotlib-users mailing list
>> Mat...@li...
>> https://lists.sourceforge.net/lists/listinfo/matplotlib-users
>> 
>> 
> 
> yes it was lot easier, but i had to set the vmin and vmax kwargs or it
> wouldn't work:
>             sigbrowse=figure()
>             x=self.stData.Data[items[0]]
>             y=self.stData.Data[items[1]]
>             z=self.stData.Data[items[2]]
>             scatter(x,y,c=z,faceted=False,vmin=z.min(),vmax=z.max())
>             colorbar()
>             show()
> 
> 

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