Re: [luabind] Iterating through a table (luabind::object)

[anders l. <and...@gm...>]

Dereferencing the iterator gives you a luabind::object, similarly object.ke=
y()
gives you another object. Use object_cast<> to get your data back

for ( luabind::iterator i( myLuaObject ), end; i !=3D end; ++i )
{
    string strKey =3D object_cast<string>( i.key() );

    luabind::object val =3D *i;

    if ( luabind::type( val ) =3D=3D LUA_TNUMBER )
    {
        // ... deal with number type e.g. object_cast<double>( val )
    }
    else if ( luabind::type( val ) =3D=3D LUA_TSTRING )
    {
        // deal with string type e.g. object_cast<string>( val )
    }
    else
    {
        // handle error
    }
}

Anders

On 5/11/06, Jesse Van Beurden <be...@in...> wrote:
>
> Hi,
> I'd like to iterate through a lua table just printing out the key/value
> along the way. I'm not really sure how to get the data out of the iterato=
r
> though.
>
> Here is what I have so far (myLuaObject is guaranteed to be a table):
>
> //...
> for(luabind::iterator i(myLuaObject), end; i !=3D end; i++) {
>     printf("%s =3D %s (or %d for 'number')\n", __KEY__, __VALUE__);
> }
> //...
>
> I believe i.key() gives a luabind object? How do you get the string for
> the key out of it? And how do you extract the string (or number) for the
> value as well (type(value) is also guaranteed to always be either 'string=
'
> or 'number')? I haven't been able to find an answer by searching the
> mailing list, or reading the luabind source.
>
> Thank you,
> Jesse Van Beurden.
>
>
>
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