Re: [Jython-users] Embedding

[Kevin B. <kb...@ca...>]

The problem is you don't have MyClass or MyObject in the Python namespace.

import org.python.util.PythonInterpreter; 
import org.python.core.*; 

public class Te { 
    public static void main(String []args) throws PyException
    { 
        PythonInterpreter interp = new PythonInterpreter();
        MyClass MyObject = new MyClass();     // A class created by me

        // how do I do this?
        interp.set( "MyObject", MyObject );
        interp.exec("MyObject.doSomething()");
        // or
        interp.set( "MyClass", MyClass.class );
        interp.exec( "MyClass().doSomething()" );
        
    }
}

class MyClass
{
    public void doSomething() {}
}


kb

> John Young wrote:
> 
> quick question with embedding jython.... in the following example (from the embedding 'tutorial' at jython.org)
> how do I access MyClass from within the python code?
> 
> 
> import org.python.util.PythonInterpreter;
> import org.python.core.*;
> 
> public class SimpleEmbedded {
>     public static void main(String []args) throws PyException
>     {
>         PythonInterpreter interp = new PythonInterpreter();
>         MyClass MyObject = new MyClass();     // A class created by me
> 
>         System.out.println("Hello, brave new world");
>         interp.exec("import sys");
>         interp.exec("print sys");
> 
>         // how do I do this?
>         // interp.exec("MyObject.doSomething()");
> 
>         interp.set("a", new PyInteger(42));
>         interp.exec("print a");
>         interp.exec("x = 2+2");
>         PyObject x = interp.get("x");
> 
>         System.out.println("x: "+x);
>         System.out.println("Goodbye, cruel world");
>     }
> }
> 
> class MyClass
> {
>     public void doSomething(){}
> }
> 
> 
> 
>