Re: [Jython-users] overload method signature

[Samuele P. <ped...@bl...>]

Hi.

> Hi All,
>
> I intended to have a method in a class that have an overload method. I
> have the following code in Test.py:
>
> class Test:
>     def __init__(self):
>         self.autoCommit = 1;
>     def Commit(self, commit=self.autoCommit):
>         self.autoCommit = commit;
>
> When executing it in Jython, I got the following error:
>
> >>> execfile("Test.py")
> Traceback (innermost last):
>   File "<console>", line 1, in ?
>   File "Test.py", line 1, in ?
>   File "Test.py", line 4, in Test
> NameError: self
>
> Basically it complain about the Commit method signature.  What's the
> correct way of doing this in Jython?  Thanks.
>

The problem you're seeing is because default argument expressions
are evaluated at function definition time not each time the function is
invoked,
so the reference to self in commit= does not make sense.
A possible working rewrite is:

     def Commit(self, commit=None):
         if commit is None:
            commit = self.autoCommit
        self.autoCommit = commit

Btw you don't need to terminate statements with ';'
It is used  to separate simple statements on a same
line,  not a very usual practice in Python.

regards, Samuele Pedroni