RE: [Jython-users] 2.1b2 PyServlet.loadServlet 'invalid syntax'

[Updike, C. <Cla...@jh...>]

Finn Bock suggested removing the tabs in front of the class declaration and
indeed that did the trick (they were the result of a cut/paste I did on the
Hello.py servlet).  Thanks to Finn for the suggestion.

Tech support on a Sunday two days before Christmas... God bless open source
and the people that make it happen.

-Clark

> I'm trying to run the Hello.py servlet example but I get the exception >
from PyServlet.loadServlet() shown below.  The strange thing is that I > can
execute the statement execfile('C:\Program Files\Apache Tomcat
> 4.0\webapps\JythonServlet\Hello.py') from the interactive interpreter
> without getting the 'invalid syntax' problem (which I think shows that >
the path is valid).  Anyone have any ideas?
> 
> TIA, 
> Clark 
> 
> javax.servlet.ServletException: Could not create Jython servletTraceback
> (innermost last): 
>  (no code object) at line 0 
> SyntaxError: ('invalid syntax', ('C:\Program Files\Apache Tomcat
> 4.0\webapps\JythonServlet\Hello.py', 3, 9, '        class
> Hello(javax.servlet.http.HttpServlet):'))
<snip>