Re: [Jython-users] List problem

[Kevin B. <kb...@ca...>]

That's cool!  :-)

It looks like what is happening is that the 'for i in a:' tracks the index it is working on, so if you remove items, you get every other one:

>>> a = range( 10 )
>>> for i in a:
...   print i
...   a.remove( i )
... 
0
2
4
6
8
>>> 

You can make a copy of the list, and iterate over that copy:

>>> a = range( 10 )
>>> for i in tuple(a):
...   print i
...   a.remove( i )
... 
0
1
2
3
4
5
6
7
8
9
>>> a
[]
>>> 

kb

Kevin McNamee wrote:
> 
> Hi,
> 
> why does the following not work:
> 
> a = [1, 2]
> for i in a:
>         a.remove(i)
> 
> The loop exits after the first iteration leaving a = [2]
> 
> How do I get around this problem?
> 
> Any help appreciated,
> Kevin
> 
> _________________________________________________
> Name/Title : Kevin McNamee, Software Consultant
> Phone      : +46 13 32 1165
> 
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