Re: [Jython-users] Creating an n byte file efficiently

[Charlie G. <cha...@gm...>]

It is.  You could do the same thing as Jeff in Python using seek:

>>> a = open('blah', 'w')
>>> a.seek(1024 * 1024 * 10)
>>> a.write('\x00')
>>> a.close()

Charlie

On Jan 17, 2008 11:50 AM, Jesse Millan <j.L...@gm...> wrote:
> Correct me if I'm wrong, but in this case, isn't the entire string is
> stored in memory?
>
>
> On Jan 17, 2008 11:46 AM, Gert-Jan <jy...@gj...> wrote:
> > You can also use a 'python only' version
> >
> > filOutput = file('textfile', 'w')
> > filOutput.write('a'*10*1024*1024)
> > filOutput.close()
> >
> > This file is filled with 'a's and 10MB. (Using a single-byte
> > codepage/encoding)
> >
> >
> >
> > Jeff Emanuel schreef:
> >
> > > This works pretty fast, but it fills the file with zeros,
> > > not text.
> > >
> > >   >>> import java
> > >   >>> raf=java.io.RandomAccessFile("path_to_file","rw")
> > >   >>> raf.setLength(1024*1024*10)
> > >   >>> raf.close()
> > >
> > >
> > > Jesse Millan wrote:
> > >> All,
> > >>
> > >> I'm looking for an efficient way to create a large dummy file in
> > >> jython. It'll need to be created and filled with about 10 MB of
> > >> (arbitrary - preferably text) data all at once. Obviously using a for
> > >> loop and calling PyFile.write("a") ten million times is a bad idea
> > >> memory wise... any suggestions?
> > >>
> > >> Thanks!
> > >>
> > >> -Jesse
> > >>
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