It's hard to tell without the servlet file, but make sure the file Hello.=
py
has a single class called 'Hello' that extends from HttpServlet:
class Hello(HttpServlet):
...
Could you post the servlet code as this would help tremendously.
hope this helps,
brian
> -----Original Message-----
> From: jyt...@li...
> [mailto:jyt...@li...]On Behalf Of Eduardo
> Jesus Fernandez Corrales
> Sent: Tuesday, March 13, 2001 3:43 AM
> To: jyt...@li...
> Subject: [Jython-users] compiled servlet does not run
>
>
> Hello everyone:
>
> I am trying to run a compiled servlet written in Jython. Here's
> what I have done
>
> - I have installed Jython 2.0 in windows NT workstation with
> servicepack 6, using java 1.2.2
> - Wrote the servlet in file Hello.py. This is the usual simple
> servlet that just prints hello world
> - Compiled the servlet with jythonc. I get some deprecation
> warnings but the Hello.class file gets generated.
> - Moved the .class to the servlet directory (Other servlets like
> IsItWorkign run fine. This is Apache 1.3.6 with Jserv 1.0)
> - Tried to run the servlet. The browser just hangs there and I
> get a timeout
>
> Looking at the apache logs I get this in the error.log file:
>
> Java Traceback:
>
> at org.python.core.Py.AttributeError(Py.java:90)
> at org.python.core.PyObject.__getattr__(PyObject.java:672)
> at org.python.core.Py.initProxy(Py.java, Compiled Code)
> at Hello.<init>(Hello.java:141)
> at java.lang.Class.newInstance0(Native Method)
> at java.lang.Class.newInstance(Class.java, Compiled Code)
> at
> org.apache.jserv.JServServletManager.load_init(JServServletManager.java=
)
> at
> org.apache.jserv.JServServletManager.loadServlet(JServServletManager.ja=
va)
> at
> org.apache.jserv.JServConnection.processRequest(JServConnection.java)
> at org.apache.jserv.JServConnection.run(JServConnection.java)
> at java.lang.Thread.run(Thread.java:479)
> Traceback (innermost last):
> (no code object) at line 0
> AttributeError: class 'Hello' has no attribute 'Hello'
>
> What could be the problem?
>
> Thanks in advance.
>
>
> --
> Eduardo J. Fern=E1ndez Corrales
>
>
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> Jyt...@li...
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