php.jsf var color definition

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#402 php.jsf var color definition

Milestone: Unknown

Status: open

Owner: nobody

Labels: php syntax (1)

Applies To: v4.6

Priority: 5

Updated: 2024-02-06

Created: 2019-07-25

Creator: Zsombor

Private: No

In php.jsf, the "=Variable" line seems to be ignored, therefore the color appearance is broken.
Changing it to "=Var" , it works again.

Discussion

Zsombor - 2019-07-25

this patch solves the issue.

php-syntax-fix.patch

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John J. Jordan - 2024-02-06

Can you describe what you mean by working and broken? What scheme is being used? The PHP syntax never references "Var" so that change shouldn't have any effect.

Perhaps this is because DefinedIdent isn't rooted on Ident? Does this change have the desired effect:

=Variable +DefinedIdent +Ident
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