Thread: Re: [Flashforth-devel] C stack - passing the params (pic24/33)
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From: Mikael N. <mik...@pp...> - 2014-07-16 06:52:26
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<div style="font-size:10pt;"><p style="margin-top:0;margin-bottom:0;">Probably, but check the xc16 help section. I think it describes the parameter passing.</p><p style="margin-top:0;margin-bottom:0;">Mike</p><p style="margin-top:0;margin-bottom:0;"> </p><div><signature_tag><p style="margin-top:0;margin-bottom:0;">Sent from my LG Mobile</p></signature_tag></div><p id="last_enter" style="margin-top:0;margin-bottom:0;"> </p><p style="margin-top:0;margin-bottom:0;"> </p><p style="margin-top:0;margin-bottom:0;">------ Original message------</p> <p style="margin-top:0;margin-bottom:0;"><b>From: </b>pito<pi...@vo...></p><p style="margin-top:0;margin-bottom:0;"><b>Date: </b>Wed, 16/07/2014 02:52</p><p style="margin-top:0;margin-bottom:0;"><b>To: </b>flashforth-devel;</p><p style="margin-top:0;margin-bottom:0;"><b>Subject:</b>[Flashforth-devel] C stack - passing the params (pic24/33)</p><p style="margin-top:0;margin-bottom:0;"> </p><pre>In the C example we pass a single 16bit short param: mov [W14], W0 .extern C4add call _C4add mov W0, [W14] So my current understanding is to pass 4 shorts (2 floats) would mean something like this: ( f1l f1h f2l f2h -- fl fh ) mov [W14--], W0 ; f2h mov [W14--], W1 ; f2l mov [W14--], W2 ; f1h mov [W14], W3 ; f1l .extern Cfadd call _Cfadd mov W0, [W14++] ; fl mov W1, [W14] ; fh Am I correct?? Thanks, P. ------------------------------------------------------------------------------ Want fast and easy access to all the code in your enterprise? Index and search up to 200,000 lines of code with a free copy of Black Duck Code Sight - the same software that powers the world's largest code search on Ohloh, the Black Duck Open Hub! Try it now. http://p.sf.net/sfu/bds _______________________________________________ Flashforth-devel mailing list Fla...@li... https://lists.sourceforge.net/lists/listinfo/flashforth-devel </pre></div> |
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From: pito <pi...@vo...> - 2014-07-16 07:49:28
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It works basically, but the order of the operands and its words is weird, so I have to swap everything before calling Cfsub. So the order of the shorts passed needs to be rearranged.. "30000 - 10000" = 10000 s>f swap 30000 s>f swap Cf- f. 20000.0 ok<#,ram> However, even with 2 addtional swaps I get following result for Cfsub: forth version: bench- 2.72317E3 CPU INSTRs per f- ok<#,ram> Cf- version: bench- 283.740E0 CPU INSTRs per f- ok<#,ram> So the C version of the f- is ~10x faster than the forth version. Nice... Pito ______________________________________________________________ > Od: Mikael Nordman <mik...@pp...> > Komu: <pi...@vo...>, <fla...@li...> > Datum: 16.07.2014 08:53 > Předmět: Re: [Flashforth-devel] C stack - passing the params (pic24/33) > >Probably, but check the xc16 help section. I think it describes the parameter passing. > >Mike > >Sent from my LG Mobile > >------ Original message------ > >From: pito > >Date: Wed, 16/07/2014 02:52 > >To: flashforth-devel; > >Subject:[Flashforth-devel] C stack - passing the params (pic24/33) > >In the C example we pass a single 16bit short param: mov [W14], W0 .extern C4add call _C4add mov W0, [W14] So my current understanding is to pass 4 shorts (2 floats) would mean something like this: ( f1l f1h f2l f2h -- fl fh ) mov [W14--], W0 ; f2h mov [W14--], W1 ; f2l mov [W14--], W2 ; f1h mov [W14], W3 ; f1l .extern Cfadd call _Cfadd mov W0, [W14++] ; fl mov W1, [W14] ; fh Am I correct?? Thanks, P. ------------------------------------------------------------------------------ Want fast and easy access to all the code in your enterprise? Index and search up to 200,000 lines of code with a free copy of Black Duck Code Sight - the same software that powers the world's largest code search on Ohloh, the Black Duck Open Hub! Try it now. http://p.sf.net/sfu/bds _______________________________________________ Flashforth-devel mailing list Fla...@li... https://lists.sourceforge.net/lists/listinfo/flashforth-devel > |
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From: pito <pi...@vo...> - 2014-07-16 08:29:21
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Ok, reordered: 100000. d>f 7 s>f Cf/ ok<#,ram> 14043 18015 f. 14285.7 ok<#,ram> 1000000. d>f 7 s>f Cf/ fs. 1.42857E5 ok<#,ram> forth: bench/ 13.2768E3 CPU INSTRs per f/ ok<#,ram> Cf/: bench/ 435.743E0 CPU INSTRs per f/ ok<#,ram> 13276 / 436 = 30x faster Nice.. Pito. ______________________________________________________________ > Od: "pito" <pi...@vo...> > Komu: Mikael Nordman <mik...@pp...>, "flashforth-devel" <fla...@li...> > Datum: 16.07.2014 09:49 > Předmět: Re: [Flashforth-devel] C stack - passing the params (pic24/33) > >It works basically, but the order of the operands and its words is weird, so I have to swap everything before calling Cfsub. >So the order of the shorts passed needs to be rearranged.. > >"30000 - 10000" = > >10000 s>f swap 30000 s>f swap Cf- f. 20000.0 ok<#,ram> > >However, even with 2 addtional swaps I get following result for Cfsub: > >forth version: >bench- 2.72317E3 CPU INSTRs per f- ok<#,ram> > >Cf- version: >bench- 283.740E0 CPU INSTRs per f- ok<#,ram> > >So the C version of the f- is ~10x faster than the forth version. Nice... > >Pito > > > > > >______________________________________________________________ >> Od: Mikael Nordman <mik...@pp...> >> Komu: <pi...@vo...>, <fla...@li...> >> Datum: 16.07.2014 08:53 >> Předmět: Re: [Flashforth-devel] C stack - passing the params (pic24/33) >> >>Probably, but check the xc16 help section. I think it describes the parameter passing. >> >>Mike >> >>Sent from my LG Mobile >> >>------ Original message------ >> >>From: pito >> >>Date: Wed, 16/07/2014 02:52 >> >>To: flashforth-devel; >> >>Subject:[Flashforth-devel] C stack - passing the params (pic24/33) >> >>In the C example we pass a single 16bit short param: mov [W14], W0 .extern C4add call _C4add mov W0, [W14] So my current understanding is to pass 4 shorts (2 floats) would mean something like this: ( f1l f1h f2l f2h -- fl fh ) mov [W14--], W0 ; f2h mov [W14--], W1 ; f2l mov [W14--], W2 ; f1h mov [W14], W3 ; f1l .extern Cfadd call _Cfadd mov W0, [W14++] ; fl mov W1, [W14] ; fh Am I correct?? Thanks, P. ------------------------------------------------------------------------------ Want fast and easy access to all the code in your enterprise? Index and search up to 200,000 lines of code with a free copy of Black Duck Code Sight - the same software that powers the world's largest code search on Ohloh, the Black Duck Open Hub! Try it now. http://p.sf.net/sfu/bds _______________________________________________ Flashforth-devel mailing list Fla...@li... https://lists.sourceforge.net/lists/listinfo/flashforth-devel >> > |
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From: pito <pi...@vo...> - 2014-07-16 09:31:45
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4 float primitives added, now the benchmarks (empty loop not subtracted): Cfloats: be 35.0069E0 CPU INSTRs per empty loop ok<#,ram> b+ 279.134E0 CPU INSTRs per f+ ok<#,ram> b- 277.291E0 CPU INSTRs per f- ok<#,ram> b* 171.349E0 CPU INSTRs per f* ok<#,ram> b/ 435.743E0 CPU INSTRs per f/ ok<#,ram> forth: be 35.0069E0 CPU INSTRs per empty loop ok<#,ram> b+ 2.49101E3 CPU INSTRs per f+ ok<#,ram> b- 2.72317E3 CPU INSTRs per f- ok<#,ram> b* 26.6107E3 CPU INSTRs per f* ok<#,ram> b/ 13.2768E3 CPU INSTRs per f/ ok<#,ram> Interestingly the forth's version of f/ is faster than f*... :) >From 11x to 190x speedup.. Nice! The next step is to add the another 30 floating point functions.. :) Pito ______________________________________________________________ > Od: "pito" <pi...@vo...> > Komu: Mikael Nordman <mik...@pp...>, "flashforth-devel" <fla...@li...> > Datum: 16.07.2014 10:29 > Předmět: Re: [Flashforth-devel] C stack - passing the params (pic24/33) > >Ok, reordered: > >100000. d>f 7 s>f Cf/ ok<#,ram> 14043 18015 >f. 14285.7 ok<#,ram> > >1000000. d>f 7 s>f Cf/ fs. 1.42857E5 ok<#,ram> > >forth: >bench/ 13.2768E3 CPU INSTRs per f/ ok<#,ram> > >Cf/: >bench/ 435.743E0 CPU INSTRs per f/ ok<#,ram> > >13276 / 436 = 30x faster >Nice.. >Pito. > > >______________________________________________________________ >> Od: "pito" <pi...@vo...> >> Komu: Mikael Nordman <mik...@pp...>, "flashforth-devel" <fla...@li...> >> Datum: 16.07.2014 09:49 >> Předmět: Re: [Flashforth-devel] C stack - passing the params (pic24/33) >> >>It works basically, but the order of the operands and its words is weird, so I have to swap everything before calling Cfsub. >>So the order of the shorts passed needs to be rearranged.. >> >>"30000 - 10000" = >> >>10000 s>f swap 30000 s>f swap Cf- f. 20000.0 ok<#,ram> >> >>However, even with 2 addtional swaps I get following result for Cfsub: >> >>forth version: >>bench- 2.72317E3 CPU INSTRs per f- ok<#,ram> >> >>Cf- version: >>bench- 283.740E0 CPU INSTRs per f- ok<#,ram> >> >>So the C version of the f- is ~10x faster than the forth version. Nice... >> >>Pito >> >> >> >> >> >>______________________________________________________________ >>> Od: Mikael Nordman <mik...@pp...> >>> Komu: <pi...@vo...>, <fla...@li...> >>> Datum: 16.07.2014 08:53 >>> Předmět: Re: [Flashforth-devel] C stack - passing the params (pic24/33) >>> >>>Probably, but check the xc16 help section. I think it describes the parameter passing. >>> >>>Mike >>> >>>Sent from my LG Mobile >>> >>>------ Original message------ >>> >>>From: pito >>> >>>Date: Wed, 16/07/2014 02:52 >>> >>>To: flashforth-devel; >>> >>>Subject:[Flashforth-devel] C stack - passing the params (pic24/33) >>> >>>In the C example we pass a single 16bit short param: mov [W14], W0 .extern C4add call _C4add mov W0, [W14] So my current understanding is to pass 4 shorts (2 floats) would mean something like this: ( f1l f1h f2l f2h -- fl fh ) mov [W14--], W0 ; f2h mov [W14--], W1 ; f2l mov [W14--], W2 ; f1h mov [W14], W3 ; f1l .extern Cfadd call _Cfadd mov W0, [W14++] ; fl mov W1, [W14] ; fh Am I correct?? Thanks, P. ------------------------------------------------------------------------------ Want fast and easy access to all the code in your enterprise? Index and search up to 200,000 lines of code with a free copy of Black Duck Code Sight - the same software that powers the world's largest code search on Ohloh, the Black Duck Open Hub! Try it now. http://p.sf.net/sfu/bds _______________________________________________ Flashforth-devel mailing list Fla...@li... https://lists.sourceforge.net/lists/listinfo/flashforth-devel >>> >> > |
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From: pito <pi...@vo...> - 2014-07-16 09:51:30
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And a final benchmark this week - the fsin fcos ftan fatan written in forth, and in forth but with 4 Cfloat primitives: forth: bsin 315.614E3 CPU INSTRs per fsin ok<#,ram> bcos 317.457E3 CPU INSTRs per fcos ok<#,ram> btan 645.600E3 CPU INSTRs per ftan ok<#,ram> batan 95.9004E3 CPU INSTRs per fatan ok<#,ram> Cfloat 4 primitives: bsin 20.9120E3 CPU INSTRs per fsin ok<#,ram> bcos 20.6356E3 CPU INSTRs per fcos ok<#,ram> btan 42.2846E3 CPU INSTRs per ftan ok<#,ram> batan 2.11884E3 CPU INSTRs per fatan ok<#,ram> 15x faster for sin cos tan, 45x for atan (a simple algorithm only). These trigo functions will be even much faster when called from C directly .. :) Pito ______________________________________________________________ > Od: "pito" <pi...@vo...> > Komu: Mikael Nordman <mik...@pp...>, "flashforth-devel" <fla...@li...> > Datum: 16.07.2014 11:31 > Předmět: Re: [Flashforth-devel] C stack - passing the params (pic24/33) > >4 float primitives added, now the benchmarks (empty loop not subtracted): > >Cfloats: >be 35.0069E0 CPU INSTRs per empty loop ok<#,ram> >b+ 279.134E0 CPU INSTRs per f+ ok<#,ram> >b- 277.291E0 CPU INSTRs per f- ok<#,ram> >b* 171.349E0 CPU INSTRs per f* ok<#,ram> >b/ 435.743E0 CPU INSTRs per f/ ok<#,ram> > > >forth: >be 35.0069E0 CPU INSTRs per empty loop ok<#,ram> >b+ 2.49101E3 CPU INSTRs per f+ ok<#,ram> >b- 2.72317E3 CPU INSTRs per f- ok<#,ram> >b* 26.6107E3 CPU INSTRs per f* ok<#,ram> >b/ 13.2768E3 CPU INSTRs per f/ ok<#,ram> > >Interestingly the forth's version of f/ is faster than f*... :) > >From 11x to 190x speedup.. > >Nice! > >The next step is to add the another 30 floating point functions.. :) > >Pito > >______________________________________________________________ >> Od: "pito" <pi...@vo...> >> Komu: Mikael Nordman <mik...@pp...>, "flashforth-devel" <fla...@li...> >> Datum: 16.07.2014 10:29 >> Předmět: Re: [Flashforth-devel] C stack - passing the params (pic24/33) >> >>Ok, reordered: >> >>100000. d>f 7 s>f Cf/ ok<#,ram> 14043 18015 >>f. 14285.7 ok<#,ram> >> >>1000000. d>f 7 s>f Cf/ fs. 1.42857E5 ok<#,ram> >> >>forth: >>bench/ 13.2768E3 CPU INSTRs per f/ ok<#,ram> >> >>Cf/: >>bench/ 435.743E0 CPU INSTRs per f/ ok<#,ram> >> >>13276 / 436 = 30x faster >>Nice.. >>Pito. >> >> >>______________________________________________________________ >>> Od: "pito" <pi...@vo...> >>> Komu: Mikael Nordman <mik...@pp...>, "flashforth-devel" <fla...@li...> >>> Datum: 16.07.2014 09:49 >>> Předmět: Re: [Flashforth-devel] C stack - passing the params (pic24/33) >>> >>>It works basically, but the order of the operands and its words is weird, so I have to swap everything before calling Cfsub. >>>So the order of the shorts passed needs to be rearranged.. >>> >>>"30000 - 10000" = >>> >>>10000 s>f swap 30000 s>f swap Cf- f. 20000.0 ok<#,ram> >>> >>>However, even with 2 addtional swaps I get following result for Cfsub: >>> >>>forth version: >>>bench- 2.72317E3 CPU INSTRs per f- ok<#,ram> >>> >>>Cf- version: >>>bench- 283.740E0 CPU INSTRs per f- ok<#,ram> >>> >>>So the C version of the f- is ~10x faster than the forth version. Nice... >>> >>>Pito >>> >>> >>> >>> >>> >>>______________________________________________________________ >>>> Od: Mikael Nordman <mik...@pp...> >>>> Komu: <pi...@vo...>, <fla...@li...> >>>> Datum: 16.07.2014 08:53 >>>> Předmět: Re: [Flashforth-devel] C stack - passing the params (pic24/33) >>>> >>>>Probably, but check the xc16 help section. I think it describes the parameter passing. >>>> >>>>Mike >>>> >>>>Sent from my LG Mobile >>>> >>>>------ Original message------ >>>> >>>>From: pito >>>> >>>>Date: Wed, 16/07/2014 02:52 >>>> >>>>To: flashforth-devel; >>>> >>>>Subject:[Flashforth-devel] C stack - passing the params (pic24/33) >>>> >>>>In the C example we pass a single 16bit short param: mov [W14], W0 .extern C4add call _C4add mov W0, [W14] So my current understanding is to pass 4 shorts (2 floats) would mean something like this: ( f1l f1h f2l f2h -- fl fh ) mov [W14--], W0 ; f2h mov [W14--], W1 ; f2l mov [W14--], W2 ; f1h mov [W14], W3 ; f1l .extern Cfadd call _Cfadd mov W0, [W14++] ; fl mov W1, [W14] ; fh Am I correct?? Thanks, P. ------------------------------------------------------------------------------ Want fast and easy access to all the code in your enterprise? Index and search up to 200,000 lines of code with a free copy of Black Duck Code Sight - the same software that powers the world's largest code search on Ohloh, the Black Duck Open Hub! Try it now. http://p.sf.net/sfu/bds _______________________________________________ Flashforth-devel mailing list Fla...@li... https://lists.sourceforge.net/lists/listinfo/flashforth-devel >>>> >>> >> > |
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From: pito <pi...@vo...> - 2014-07-16 10:57:06
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I cannot resist to add the others: 777 s>f 1000 s>f f/ fconstant arg \ = 0.777 ok<#,ram> arg fsin fs. 7.01144E-1 ok<#,ram> arg fcos fs. 7.13020E-1 ok<#,ram> arg ftan fs. 9.83343E-1 ok<#,ram> arg fsqrt fs. 8.81476E-1 ok<#,ram> arg fexp fs. 2.17494E0 ok<#,ram> arg flog fs. -2.52315E-1 ok<#,ram> arg arg fpow fs. 8.21972E-1 ok<#,ram> pure C functions called from FF: bsin 2.26716E3 CPU INSTRs per fsin ok<#,ram> bcos 3.03178E3 CPU INSTRs per fcos ok<#,ram> btan 2.90925E3 CPU INSTRs per ftan ok<#,ram> blog 2.53247E3 CPU INSTRs per flog ok<#,ram> bexp 3.04007E3 CPU INSTRs per fexp ok<#,ram> bsqrt 525.103E0 CPU INSTRs per fsqrt ok<#,ram> 7-9x faster than the same with 4 Cfloat primitves and forth.. ;) Very nice! Pito. ______________________________________________________________ > Od: "pito" <pi...@vo...> > Komu: Mikael Nordman <mik...@pp...>, "flashforth-devel" <fla...@li...> > Datum: 16.07.2014 11:51 > Předmět: Re: [Flashforth-devel] C stack - passing the params (pic24/33) > >And a final benchmark this week - the fsin fcos ftan fatan written in forth, and in forth but with 4 Cfloat primitives: > >forth: >bsin 315.614E3 CPU INSTRs per fsin ok<#,ram> >bcos 317.457E3 CPU INSTRs per fcos ok<#,ram> >btan 645.600E3 CPU INSTRs per ftan ok<#,ram> >batan 95.9004E3 CPU INSTRs per fatan ok<#,ram> > >Cfloat 4 primitives: >bsin 20.9120E3 CPU INSTRs per fsin ok<#,ram> >bcos 20.6356E3 CPU INSTRs per fcos ok<#,ram> >btan 42.2846E3 CPU INSTRs per ftan ok<#,ram> >batan 2.11884E3 CPU INSTRs per fatan ok<#,ram> > >15x faster for sin cos tan, 45x for atan (a simple algorithm only). >These trigo functions will be even much faster when called from C directly .. :) >Pito > >______________________________________________________________ >> Od: "pito" <pi...@vo...> >> Komu: Mikael Nordman <mik...@pp...>, "flashforth-devel" <fla...@li...> >> Datum: 16.07.2014 11:31 >> Předmět: Re: [Flashforth-devel] C stack - passing the params (pic24/33) >> >>4 float primitives added, now the benchmarks (empty loop not subtracted): >> >>Cfloats: >>be 35.0069E0 CPU INSTRs per empty loop ok<#,ram> >>b+ 279.134E0 CPU INSTRs per f+ ok<#,ram> >>b- 277.291E0 CPU INSTRs per f- ok<#,ram> >>b* 171.349E0 CPU INSTRs per f* ok<#,ram> >>b/ 435.743E0 CPU INSTRs per f/ ok<#,ram> >> >> >>forth: >>be 35.0069E0 CPU INSTRs per empty loop ok<#,ram> >>b+ 2.49101E3 CPU INSTRs per f+ ok<#,ram> >>b- 2.72317E3 CPU INSTRs per f- ok<#,ram> >>b* 26.6107E3 CPU INSTRs per f* ok<#,ram> >>b/ 13.2768E3 CPU INSTRs per f/ ok<#,ram> >> >>Interestingly the forth's version of f/ is faster than f*... :) >> >>From 11x to 190x speedup.. >> >>Nice! >> >>The next step is to add the another 30 floating point functions.. :) >> >>Pito >> >>______________________________________________________________ >>> Od: "pito" <pi...@vo...> >>> Komu: Mikael Nordman <mik...@pp...>, "flashforth-devel" <fla...@li...> >>> Datum: 16.07.2014 10:29 >>> Předmět: Re: [Flashforth-devel] C stack - passing the params (pic24/33) >>> >>>Ok, reordered: >>> >>>100000. d>f 7 s>f Cf/ ok<#,ram> 14043 18015 >>>f. 14285.7 ok<#,ram> >>> >>>1000000. d>f 7 s>f Cf/ fs. 1.42857E5 ok<#,ram> >>> >>>forth: >>>bench/ 13.2768E3 CPU INSTRs per f/ ok<#,ram> >>> >>>Cf/: >>>bench/ 435.743E0 CPU INSTRs per f/ ok<#,ram> >>> >>>13276 / 436 = 30x faster >>>Nice.. >>>Pito. >>> >>> >>>______________________________________________________________ >>>> Od: "pito" <pi...@vo...> >>>> Komu: Mikael Nordman <mik...@pp...>, "flashforth-devel" <fla...@li...> >>>> Datum: 16.07.2014 09:49 >>>> Předmět: Re: [Flashforth-devel] C stack - passing the params (pic24/33) >>>> >>>>It works basically, but the order of the operands and its words is weird, so I have to swap everything before calling Cfsub. >>>>So the order of the shorts passed needs to be rearranged.. >>>> >>>>"30000 - 10000" = >>>> >>>>10000 s>f swap 30000 s>f swap Cf- f. 20000.0 ok<#,ram> >>>> >>>>However, even with 2 addtional swaps I get following result for Cfsub: >>>> >>>>forth version: >>>>bench- 2.72317E3 CPU INSTRs per f- ok<#,ram> >>>> >>>>Cf- version: >>>>bench- 283.740E0 CPU INSTRs per f- ok<#,ram> >>>> >>>>So the C version of the f- is ~10x faster than the forth version. Nice... >>>> >>>>Pito >>>> >>>> >>>> >>>> >>>> >>>>______________________________________________________________ >>>>> Od: Mikael Nordman <mik...@pp...> >>>>> Komu: <pi...@vo...>, <fla...@li...> >>>>> Datum: 16.07.2014 08:53 >>>>> Předmět: Re: [Flashforth-devel] C stack - passing the params (pic24/33) >>>>> >>>>>Probably, but check the xc16 help section. I think it describes the parameter passing. >>>>> >>>>>Mike >>>>> >>>>>Sent from my LG Mobile >>>>> >>>>>------ Original message------ >>>>> >>>>>From: pito >>>>> >>>>>Date: Wed, 16/07/2014 02:52 >>>>> >>>>>To: flashforth-devel; >>>>> >>>>>Subject:[Flashforth-devel] C stack - passing the params (pic24/33) >>>>> >>>>>In the C example we pass a single 16bit short param: mov [W14], W0 .extern C4add call _C4add mov W0, [W14] So my current understanding is to pass 4 shorts (2 floats) would mean something like this: ( f1l f1h f2l f2h -- fl fh ) mov [W14--], W0 ; f2h mov [W14--], W1 ; f2l mov [W14--], W2 ; f1h mov [W14], W3 ; f1l .extern Cfadd call _Cfadd mov W0, [W14++] ; fl mov W1, [W14] ; fh Am I correct?? Thanks, P. ------------------------------------------------------------------------------ Want fast and easy access to all the code in your enterprise? Index and search up to 200,000 lines of code with a free copy of Black Duck Code Sight - the same software that powers the world's largest code search on Ohloh, the Black Duck Open Hub! Try it now. http://p.sf.net/sfu/bds _______________________________________________ Flashforth-devel mailing list Fla...@li... https://lists.sourceforge.net/lists/listinfo/flashforth-devel >>>>> >>>> >>> >> > |
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