Matlab currents read

[Dor BA]

Hi,
Is there a Matlab order similar to:
DSSCircuit.AllNodeVmagPUByPhase
regarding currents?

Best Regards,
Dor

[Davis Montenegro]

Hello,

It all depends on what you are asking for. If what you are looking for is the vectorcontaining complex injection currents for the present solution, then yes, the property is as follows:

DSSCircuit.YCurrents;

Otherwise, if what you are looking for is a vector containing the currents flowing though the circuit's PDElements (lines, transformers), then there is no interface for that. What you can do is to use the Lines interface and the CktElement interface to get that information, something as follows:

 DSSLines        =   DSSCircuit.Lines;
DSSCktElement   =   DSSCircuit.ActiveCktElement; 
DSSLines.First;
MyCurrents      =   []
for i=1:DSSLines.Count,
    MyCurrents    =   [MyCurrents, DSSCktElement.currents];
    DSSLines.Next;
end;

Best regards

Davis

[Dor BA]

Thank you for your help Davis.

I ran your second suggestion on the IEEE37 circuit, and got a 424 length row.

Is there a way to see their names?

Also, is there a Matlab-OpenDSS manual somewhere?

Thanks again

[Davis Montenegro]

Hello,

Well, you have the code, of course you can. "DSSLines.Name" should do the job, just put it into an array. Each current is delivered as complex pair per phase of element, so you'll have to fix it at your side.

Best regards

Davis

[Davis Montenegro]

Documentation:

https://sourceforge.net/p/electricdss/code/HEAD/tree/trunk/Version8/Distrib/Doc/

Best regards

Davis

[Dor BA]

Hi Davis,

The circuit contains 36 lines, and by using DSSLines.Name I got 36 names. 35 lines are 3-phase, complex pairs, so 3532=210. Plus a one phase jumper, that's 212. But I get 424 values, which is double. What am I missing?

Thanks again
Dor

[Davis Montenegro]

Hello,

Yes, this is an easy one. Let's check the numbers:

• 1 line has 2 terminals.
• 35 lines are 3 phase, with 2 terminals, 6 readings (3 for terminal 1 and 3 for terminal 2).
• Each reading is a complex pair, ergo, 35 * 6 * 2 = 420.
• 1 line single phase, with 2 terminals, 2 readins, each reading 2 complex pairs: 1 * 2 * 2 = 4.
• Total readings = 4 + 420 = 424 values.

Best regards

Davis

[Dor BA]

I can't get it into an array, I'm probably doing something wrong

[Dor BA]

Thank you Davis, I thought so and forgot to write it here.

What about the oreder?
Is it line1:
1.terminal1 ph1_real
2.terminal1 ph1_comp

1. terminal1 ph2_real
2. terminal1 ph2_comp
3. terminal1 ph3_real
4. terminal1 ph3_comp
5. terminal2 ph1_real
   8.terminal2 ph1_comp
6. terminal2 ph2_real
7. terminal2 ph2_comp
8. terminal2 ph3_real
9. terminal2 ph3_comp

And then line2, and etc.?

[Davis Montenegro]

Yes Sir,

Best regards

Davis

[Dor BA]

Thanks again