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From: Ng C. Y. [Cyng] <cy...@cs...> - 2003-02-11 04:24:21
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Hi,
Request1 <------> S1(MSH1) <=============> R1(MSH2) <------> Request2
register register
(a,b,c,d) (e,f,g,h)
> If Request1 is to send a message directly to R1, how will it accept it,
> since it is not registered at R1 (it is only registered at MSH1).
Request1 is a client API (stub) for S1(MSH1). One makes use of
Request1 in the way that it first registers to S1(MSH1) such that S1(MSH1)
will send messages to other MSHs' *on behalf of* Request1. If you send messages
to R1 directly, that means you are somehow writing another program that
composes an ebXML message and makes HttpConnection directly to R1. This
only involves the registration of Request2 for receiving messages. No
registration is involved in the sender side.
Regards,
CY
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Ng Chi Yuen, CY. cy...@ce... http://www.cecid.hku.hk/
Technology Officer,
Centre for E-Commerce Infrastructure Development,
The University of Hong Kong
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