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From: gambarimas87 <gam...@gm...> - 2017-10-06 18:42:47
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Hi, I'm trying to match the powder patterns computed with the Debye equation and the complete integration methods. I'm using as test case an isolated Ag nanoparticle having N=3559 atoms and approximately 49 Amstrong diameter, carved from a perfect (infinite) structure. When computing the pattern with the Debye equation I realized that in order to make it equal (as it should be) to N^2 f^2 at q=2PI h = 2pi dstar = 2pi *2 sin(theta)/lambda = 0, the pattern must be scaled by a factor of 10^-4. This also makes the pattern almost equal to the one computed by the software Debyer and Powdog that make use of the Debye equation for the same purpose. So I'm wondering which is the origin of this 10^-4 factor ? When proceeding to compare the scaled Debye pattern with that computed by the complete integration method, I need to further scale the latter as well as apply some correction for its intensity, in order to match both. My first issue here is that this new scaling factor depends upon the dh, dk and dl steps used for the calculation of the intensity in reciprocal space inside the 'powder' menu. I had to tune (decrease) this 'step' parameter in order to make smother the pattern computed by the integration method. Then the “correction” that I mention is just a division of the intensity at each value of q by 4pi (q/2pi)^2 = 4pi h^2 = 4pi (2 sin(theta)/lambda)^2, i.e. the area of the sphere in reciprocal space that contributes to the diffracted intensity at h= 2 sin(theta)/lambda in a powder pattern. It looks like Discus making the integration over that sphere but without dividing the result by its area. Could you explain me why do I need to perform these modifications over the pattern computed by the integration method to match it with that from the Debye equation? I'm attaching to this message the macro I used as well as the stru file to build the Ag particle. For the pattern computed with the integration method I limit the range in q to [2.3, 3.3] A^-1, to speed up the computation, i.e. I actually compare only with the first two peaks of the powder pattern obtained with the Debye equation. Many thanks in advance Camilo Perez |