Re: [Dev-C++] feof question

[Sam <sch...@ho...>]

Thanks for all the suggestions.  I'll try them out...

Sam
  ----- Original Message -----=20
  From: Ioannis Vranos=20
  To: dev...@li...=20
  Sent: Saturday, March 17, 2001 3:25 PM
  Subject: RE: [Dev-C++] feof question


  You can also use :
  =20
  do
  {=20
  /* ... */
  }while(!feof(filePtr));
  =20
  In this way you gain one less check for end of file (where performance =
is important).
  =20
  =20
  About the second read of the "same data" at the end:
  =20
  This happens because the end of file is true only after a failed =
attempt (because the end of file has been already reached and it has no =
more to read). That means it doesn't read the data for the second time, =
but you have a failed attempt to read more data.
    As for the counter you can either decrease it by one after the loop =
or initialize it with -1.
  =20
  =20
  Ioannis
  =20
  * Ioannis Vranos
  * Programming pages: http://members.nbci.com/noicys
  * Alternative URL: http://run.to/noicys
    -----Original Message-----
    From: dev...@li... =
[mailto:dev...@li...]On Behalf Of Sam
    Sent: Saturday, March 17, 2001 8:01 PM
    To: dev...@li...
    Subject: [Dev-C++] feof question


    I'm trying to read through a file using the following statement:

    while(!feof(filePtr)
    {
       fread(&phone, sizeof(struct record), 1, filePtr);
       printf("%d%s", int, name);
       count++;
    }

    The problem is that it reads the last record twice and increments =
the count one more time than needed.  Could someone explain why this =
happens and how to avoid it using the feof function?  Thanks.

    Sam