Re: [Dev-C++] Random Number

[Jesper <hag...@ho...>]

//beginning of program
#include <iostream.h>
#include <stdlib.h>

int main()
{
  int number;
  number=3D1+rand()%13;
  cout << number;
 return 0;
}
//end of program

Try this it worked. One stupid thing is that it gives you the same =
number everytime you use it.I have forgotten how to do if you want =
diffrent numbers every time you use the program.

Anyone knows?


Jesper


----- Original Message -----=20
From: "Jose Flores" <jf...@ax...>
To: <dev...@li...>
Sent: Tuesday, February 13, 2001 5:58 PM
Subject: RE: [Dev-C++] Random Number


> I get and error  "  implicit declaration of function 'int =
random(....)' "
> when I tried the "number =3D random(13)+1;" command.  Any suggestions?
>=20
> -----Original Message-----
> From: Jesper [mailto:hag...@ho...]
> Sent: Tuesday, February 13, 2001 11:29 AM
> To: dev...@li...
> Subject: Re: [Dev-C++] Random Number
>=20
>=20
> Try this it might work:
>=20
> number =3D random(13)+1;
>=20
> Jesper
>=20
> ----- Original Message -----=20
> From: "Jose Flores" <jf...@ax...>
> To: <dev...@li...>
> Sent: Tuesday, February 13, 2001 5:16 PM
> Subject: [Dev-C++] Random Number
>=20
>=20
> > what is a good simple command to get a random number from 1 to 13?  =
I keep
> > getting the run around when I ask this question...
> > Thanks=20
> > Jose
> >=20
> > _______________________________________________
> > Dev-cpp-users mailing list
> > Dev...@li...
> > http://lists.sourceforge.net/lists/listinfo/dev-cpp-users
> >=20
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