RE: [Dev-C++] problem calling functions

[sushmita u. <sus...@ya...>]

thank u for the instructions.I will always remember it
but i don't remember whthr i have ever psted such
problem to u .any way thanks
--- James Gordon <Jam...@Cl...> wrote:
> Your function calls don't have () on the end.
> Even if you do not pass parameters to functions you
> must include empty ()
> when calling the functions.
> 
> The deceleration of inpu doesn't pass parameters but
> the definition requires
> an int.
> 
> Regards,
> 
> James.
> 
> 
> -----Original Message-----
> From: jag [mailto:won...@th...]
> Sent: Tuesday, January 16, 2001 11:33 AM
> To: devc++ mail-list
> Subject: [Dev-C++] problem calling functions
> 
> 
>
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> 
> Hi, can anyone tell me where i'm going wrong with my
> coding?  The code is at
> the end of the email.  It's a simple program to
> practice function calls.  I
> want to enter either a number 1 or number 2 to call
> seperate functions.
> When the functions are called it prints a simple
> message to say that the
> function has been successfully called, i can n't get
> the program to call the
> functions however! Can anyone advise me why?
> 
> thanks in advance
> jag.
> 
> #include <stdio.h>
> #include <iostream.h>
> int again;
> int enteb;
> void outpu(void);
> void inpu(void);
> 
> int main(int argc, char *argv[])
> 
> {
> cout <<"monkey type (1) for function outpu (1) or
> (2) for function inpu";
> 
> cin >>enteb;
> if (enteb == 1)
> {
> 
>  outpu;
> }
> 
> if (enteb == 2)
>  {
>  inpu;
>  }
> cout <<"neither 1 or 2\n";
> cout <<"wait for a number and enter pressed";
> cin >> again;
> 
>   return 0;
> }
>  void outpu(void)
> {
> 
> cout <<"calling function outpu "<<enteb;
> 
> }
> void inpu(int enteb)
> {
> 
> 
> cout <<"calling function inpu "<<enteb;
> 
> }
> ICQ #103968172
> 
> 
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