RE: [Dev-C++] problem calling functions

[James G. <Jam...@Cl...>]

Your function calls don't have () on the end.
Even if you do not pass parameters to functions you must include empty ()
when calling the functions.

The deceleration of inpu doesn't pass parameters but the definition requires
an int.

Regards,

James.


-----Original Message-----
From: jag [mailto:won...@th...]
Sent: Tuesday, January 16, 2001 11:33 AM
To: devc++ mail-list
Subject: [Dev-C++] problem calling functions


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Hi, can anyone tell me where i'm going wrong with my coding?  The code is at
the end of the email.  It's a simple program to practice function calls.  I
want to enter either a number 1 or number 2 to call seperate functions.
When the functions are called it prints a simple message to say that the
function has been successfully called, i can n't get the program to call the
functions however! Can anyone advise me why?

thanks in advance
jag.

#include <stdio.h>
#include <iostream.h>
int again;
int enteb;
void outpu(void);
void inpu(void);

int main(int argc, char *argv[])

{
cout <<"monkey type (1) for function outpu (1) or (2) for function inpu";

cin >>enteb;
if (enteb == 1)
{

 outpu;
}

if (enteb == 2)
 {
 inpu;
 }
cout <<"neither 1 or 2\n";
cout <<"wait for a number and enter pressed";
cin >> again;

  return 0;
}
 void outpu(void)
{

cout <<"calling function outpu "<<enteb;

}
void inpu(int enteb)
{


cout <<"calling function inpu "<<enteb;

}
ICQ #103968172


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