[Dev-C++] Divide error

[Frazell T. <fr...@fl...>]

I managed to fix the only bug i know of in my program i used an if =
statement but if the user enters an exit value over 40000 the program =
will then continue to execute reliving the bug if anyone can help me fix =
this new bug i would be greatly appreciative



-------------------------------------PROGRAM SOURCE =
CODE-------------------------------------------------------

// Quadrilatric equation calculater
// Written by: Frazell Thomas
#include <stdio.h>
#include <math.h>
#include <windows.h>
int a,a_2,b,c,d,answer,sroot,answer_2,b_2,b_3,div,quit,quit1;
int value[10];
int ctr =3D 0;
int nbr;
char plus;
main()
{   =20
       MessageBox (NULL, "This is Q-Calc BETA 1.1

Visit http://www.FrazellThomas.com" , "Q-Calc", 0 + MB_ICONASTERISK);
      // Cpoyright and author information
      // If you alter this program you must list me in the credits
      // As the lead developer on this piece of software
      // I would also request that any version you release
      // Be forwarded to me at fra...@ya...
      // To keep me from re-inventing the wheel (programming code u =
already
      // Done)
      // This software it under the GNU public license
      printf("This program is designed to do quadratic equations =
only.\n");
      printf("You are free to use this software as stated under the =
GNU\n");
      printf("Public License (Avalible at GNU.org).\n\n");
      printf("Version: Beta 1.1 12/12/2000 8:00PM EST.\n");
      printf("Programmer: Frazell Thomas\n");
      printf("Please visit http://www.frazellthomas.com\n\n");
      // Input From User
      printf("Please enter the number used to represent varible A: ");
      scanf("%d", &a);
      quit =3D 40000;
      // if statement to prevent the divide error if the var. a is zero
        if (a =3D=3D 0)
         {
          printf("\n\nYou entered Zero for varible A which will result =
in\n");
          printf("\n\nNo possible answer please exit the program and run =
again\n");
          printf("\n\nBut do not use A Zero for varible A\n");
          printf("\nPlease Enter 33 To Quit\n");
          scanf("%d", &quit);
         }
            if (quit <=3D 20000)
              {=20
               return 0;
              }              =20
      printf("Please enter the number used to represent varible B: ");
      scanf("%d", &b_3);
      printf("Please enter the number used to represent varible C: ");
      scanf("%d", &c);
      //Raises varible b to the second power
      a_2 =3D pow(b_3, 2);
      // This is the part of out calc prog that does the work :O)
      // please alter + sign before var. c to a - if needed and vic =
versa
      sroot =3D (a_2 - 4 * a * c);
      b_2 =3D b_3 * 2;
      b =3D b_3 - b_2;
      div =3D 2 * a;
      answer =3D (b + sroot) / div;
      answer_2 =3D (b - sroot) / div;
      // Prints the answer
      printf("\nThe Answer Is %d and %d\n ", answer, answer_2);
      printf("\nThe square root of %d in this problem was %d\n ", b_3, =
sroot);
      printf("\n%d To the second power is %d ", b_3, a_2);
     =20
      // While loop  =20
               do
         {
               puts("\n\nEnter 99 to quit ");
               scanf( "%d", &nbr);
               value[ctr] =3D nbr;
               ctr++;
         }while (ctr < 10 && nbr !=3D 99);
      return 0;
}