[Dev-C++] temperture converter problem-help needed

[J R <ray...@ya...>]

ok I'm trying to make a simple celcius, farenheit converter.  I want it to ask which you want to convert to, what temperature, and then convert.  I already have everything working prefectly except that I ask the user to type in what to convert to.  The way I have it if they type 1 it converts celcius to farenheit and 2 farenheit to celcius.  Now heres the problem.  I want it so that if a user types any number but 1 or 22 it says "invalid entry"  I have that working too but if  the user picks to type in 1 to convert celcius to farenheit right after he puts in his number it converts it and then says invalid entry.  I dont want it to say invalid entry there.  Only if the user types in something besides 1 or 2.  Heres the code any help would be great.

 

#include <iostream>
#include <string>
#include <stdlib.h>

using namespace std;

int main()
{
while(1)
{
string type;

cout << "Would you like to convert to Celcius or Farenheit?" <<endl;
cout << " " <<endl;
cout << "1. Farenheit" <<endl;
cout << " " <<endl;
cout << "2. Celcius" <<endl;
cout << " " <<endl;
cin >>type;

if (type== "1")
{
unsigned short int tempc;
cout << " " <<endl;
cout << "Please enter the Celcius temperature you wish to convert."<<endl;
cin>> tempc;
cout << " " <<endl;
unsigned short int degreefarenheit=tempc*9/5+32;
cout << " " <<endl;
cout << "Temperature in Farenheit:" << degreefarenheit <<endl;
cout << " " <<endl;
}
if (type== "2")
{
unsigned short int tempf;
cout << " " <<endl;
cout << "Please enter the farenheit temperature you wish to convert."<<endl;
cin >> tempf;
cout << " " <<endl;
unsigned short int degreecelcius=tempf-32*5/9;
cout << " " <<endl;
cout << "Temperature in Celcius:" << degreecelcius <<endl;
cout << " " <<endl;
}
else;
{
cout << "Invalid entry please try again" <<endl;
}
system("PAUSE");
}
return 0;
}


 

If you could rewrite it for me or just tell me what I did wrong it would be greatly appreciated.  

Thanks again,

J



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