RE: [Dev-C++] string-version of '+'

[James G. <Jam...@Cl...>]

this might not be the best way but I've always had to split the code into
two statements.

Change this:
myString = "John has " + myApples + " apples";

To this:
myString = "John has " + myApples;
myString += " apples";

This is because it works from right to left.
In your code you are trying to assign the string " apples" to the char[20]
and the result from that to the string "John has " and then that lot to the
std::string.

I think that's correct...

Regards,

James.


-----Original Message-----
From: Gregor Peter [mailto:Gre...@dl...]
Sent: Thursday, December 07, 2000 2:58 PM
To: exc...@sp...; dev...@li...
Subject: [Dev-C++] string-version of '+'


You're right!

I tried it before in a direkt manner which doesn't work :-(

string myString;
char myApples[20];
int    myInt;

itoa( myInt, myApples, 10);
myString = "John has " + myApples + " apples";

I get following error message:
    invalid operands `const char[28]' and `char[20]' to binary `operator +'

How do I enshure to use the string-version of '+' instead of  the integer?

Gregor


> string my1String("John has");
> string my2String("apples!");
> char myApples[20] ;
> int   myInt = 6;
>
> itoa(myInt, myApples, 10);
>
> my1String = my1String + myApples + my2String ;
>
> That is you can put all of the strings into one, my1String.

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