RE: [Dev-C++] character buffering with getch() and gets()

[Ioannis V. <no...@ya...>]

> -----Original Message-----
> From: dev...@li...
> [mailto:dev...@li...]On Behalf Of Jon Keim
> Sent: Monday, November 13, 2000 11:39 AM
> To: Dev...@li...
> Subject: [Dev-C++] character buffering with getch() and gets()
>
>
> problem 1:
>     I'm developing a piddly little program from a learning book, and in my
> main(), I've got a statement to get the user's choice from a menu
> that looks
> like this:
>
> choice = getche();
>
>     it takes the '1' character required and successfully activates a
> particular function.  Once inside the function, however, I have this input
> statement, to prompt for and get some data for the string "title" in a
> struct array.
>
> printf( "Book title : " );
> gets( catalog[ recordCount ].title );
>
>     Simple, right?  Nope.  The prompt comes up
>
> Book title : 1
>
>     the gets() reads the 1 from the getche() up in the main function...  I
> have tried all sorts of odd things, placing getch()'s and getche()'s
> after/before statements to clear the buffer, substituted a scanf( "%s",


getch(), getche() are not standard C/C++ functions. Better use getchar() or
getc(stdin) in the following style:

choice=getchar();
getchar();

getchar() is equivalent of getc(stdin) so use whatever one you like. The
second getchar() is used to clear '\n' (the enter) from the stdin.


> foo ) for the gets().  Even tried testing to see if there was something in
> the buffer with kbhit(), and that comes up negative.  Any idea why this is
> happening?


Implement my above suggestion.


> ---------------------------------------------------------------------
>
> problem 2:
>     any idea how to limit an inputted string to 80 characters and still be
> able to read spaces?  I tried the following in my above program and it
> screwed things up FAR worse...
>
> scanf( "%80[^\n]", string );

One way is fgets(): fgets(string, 80, stdin);

It reads 79 characters, and places '\0' at the end.


Ioannis


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