Re: [Dev-C++] Multiplication form

[Per W. <pw...@ia...>]

You either don't (with normal 32-bit numbers you don't have to think about
any carry for so small products...)

If this is a school work, or you are implementing a big-number library
working in decimal, you just have to keep an intermediate variable
'carry'.

carry = 0;
while (digit-columns to add) {
    column_sum = carry + digit + digit + digit + digit + ...;
    carry = column_sum / 10;
    column_sum %= 10;
    emit_digit(column_sum);
}
if (carry) emit_digit(carry);

/pwm

On Wed, 2 Apr 2008, Kenneth Chung wrote:

>
> Hi All,
>
> Consider a multiplication of the form
>
>
>                                                9 9 9
>                                           x   9 9 9
>                                               ------
>                                              8 9 9 1
>                                           8 9 9 1
>                                        8 9 9 1
>                                        -----------
>                                        9 9 8 0 0 1 <----result
>
> How do I program the result line using C code especially when the sum of numbers has 2 digits let say 10, 20 then the first digit which is the 1 or 2 has to be added to next column for next sum?
>
> Thanks for your help.
>
> regards,
> Kenneth
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