Re: [Dev-C++] Pointer location

[Siva C. <siv...@ya...>]

Hi,

First let me make a few notes which will help
understand your code better. I am assuming that you
are working on a 32 bit system. 

1. pa is a pointer of type bartek.
2. The size of the bartek datatype is 12 bytes. It is
not 9 bytes since the size in bytes should be a
multiple of 4 in a 32 bit system.
3. Since size of bartek is 12 bytes, pa+2 will point
to a location which is 24 bytes ahead of the location
pointed by pa.
4. The size of int is 4 bytes.

With the above points in mind, pa+2 points to a
location which is 24/4=6 int locations away from pa.
Which is to say that pa+2 points to the 7th integer in
the array x. The 7th integer in the array is x[6]. 

Hope I could clear your confusion.
/Siva Chandra

--- Bartosz Śliwa <ba...@o2...> wrote:

> Hi.
> 
> Could you tell me, why pointer 'pa' shows 6 element
> of the table (x[6]). Why it does not show second
> element? Here is the code:
> 
> #include <cstdlib>
> #include <iostream>
> #include <stdio.h>
> #include <conio.h>
> 
> 
> 
> using namespace std;
> 
> struct bartek {
>          int a;
>          char c[4];
>          int b;
> } *wsk1_bartek;
> 
> int x[1000];
> 
> int main(int argc, char *argv[])
> {
>     system("PAUSE");
>   
>     bartek *pa;
>     
>     pa = (bartek*) x;
>     
>     for(int i = 0 ; i < 100; ++i)   {
>             x[i] = i;
>     }
>     
> cout <<" After shift +2: " << (pa+2)->a << endl;
>     
> cout <<" Global object read on 6 position x[6]: " <<
> x[6]
> << endl;
>  
>     system("PAUSE");
> 
>     return EXIT_SUCCESS;
> 
> }
> 
> 
> ...and here is the output:
> 
> Press any key to continue...
> After shift +2: 6
> Global object on 6 position x[6]: 6
> Press any key to continue...
> 
> 
>
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