Re: [Dev-C++] Glib::ustring::assign(...)

[Jamiil A. <jal...@gm...>]

Sorry, for being so lazy and not post a more elaborate question, I hope this 
would be a better way to ask this question.

jme::Combo::Combo(const Glib::ustring& title){
   Glib::ustring* ustr;
   std::auto_ptr<Glib::ustring> ustr(new Glib::ustring("Unknown"));
   if(!title.empty()) {
        this->ustr->assign(title);
   }
}
Thanks in advance!
----- Original Message ----- 
From: "Reid Thompson" <rei...@at...>
To: "Jamiil Abduqadir" <jal...@gm...>
Cc: "'Dev Cpp MailingLinst'" <dev...@li...>
Sent: Friday, August 17, 2007 5:33 PM
Subject: Re: [Dev-C++] Glib::ustring::assign(...)


> Jamiil Abduqadir wrote:
>> std::auto_ptr<Glib::ustring> ustr(new Glib::ustring("Unknown"));
>>     if(!title.empty())
>>     {
>>         this->ustr->assign(title);  // Segmentation Fault <<=====
>>     }
>>  Be my guest.
> what's the definition of ustr????
>
>
> does this example work on your system?
>
> http://wwwasd.web.cern.ch/wwwasd/lhc++/RW/stdlibcr/aut_3512.htm
>
> //
>    // auto_ptr.cpp
>    //
>    #include <iostream.h>
>    #include <memory>
>    //
>    // A simple structure.
>    //
>    struct X
>    {
>        X (int i = 0) : m_i(i) { }
>        int get() const { return m_i; }
>        int m_i;
>    };
>    int main ()
>    {
>       //
>       // b will hold a pointer to an X.
>       //
>       auto_ptr<X> b(new X(12345));
>       //
>       // a will now be the owner of the underlying pointer.
>       //
>       auto_ptr<X> a = b;
>       //
>       // Output the value contained by the underlying pointer.
>       //
>       cout << a->get() << endl;
>       //
>       // The pointer will be deleted when a is destroyed on
>       // leaving scope.
>       //
>       return 0;
>    }
> Output :
> 12345