Re: [Dev-C++] fread get stuck

[Peeyush B. <pee...@re...>]

Hello All=0AI am facing one problem  in code below. This code is for copy c=
onstructor.=0A=0AActaully when copy constructor gets called for get functio=
n with object b , the object value becomes 0. I think that that object b & =
object p are not pointing to same location as i explicitly declared the cop=
y constructor.=0A=0APlease explain why it is so... Why object b value becom=
e 0 . Also how to avoid this so that object value should print actual value=
.=0A=0A#include<iostream>=0Ausing namespace std;=0Aclass A{=0A        stati=
c int count;=0A        int *num;=0A        public:=0A        A():num(new in=
t(2)){=0A                cout<<"Zero argument ctor called\n"<<endl;=0A     =
           count++;=0A        }=0A=0A        A(int i):num(new int(i)){=0A  =
              cout<<"One arument ctor called\n"<<endl;=0A                co=
unt++;=0A        }=0A=0A        A(const A &i):num(i.num){=0A               =
 cout<<"Copy Ctor called\n"<<endl;=0A                count++;=0A        }=
=0A=0A        void print(){=0A=0A                cout<<"count"<<count<<"Val=
ue:"<<*num<<endl;=0A        }=0A=0A        ~A(){=0A                cout<<"D=
tor called\t"<<"count"<<count--<<endl;=0A                delete num;=0A    =
    }=0A};=0A=0Avoid get(A p){=0A                cout<<"get function called=
\n"<<endl;=0A                p.print();=0A        }=0A=0A=0Aint A::count;=
=0A=0Aint main(){=0A=0AA a;=0Aa.print();=0AA b(3);=0Ab.print();=0Aget(b);=
=0Ab.print();=0AA c=3Da;=0Ac.print();=0Areturn 0;=0A}=0A=0A=0ARegards=0APee=
yush B.=0A=0A