Re: [Dev-C++] POW question

[Lukas 'C. M. <gry...@gm...>]

I'm not sure how abs() would help.. unless that's to ensure that the
original value is positive before multiplying by negative one?

-Lukas

On 6/27/05, Scott <fre...@ve...> wrote:
> =20
> =20
> > Hi...
> > try
> > -(pow(2,8)/2+1)
> > greetz
> =20
> Yeah doing it that way seems to be incorrect!!,=20
> It does provide the correct result if you change it to -(pow(2,8)/2-1)=20
>  =20
> But thanks for the reply none the less.=20
> Marco's "(pow(2,8)/2+1) * -1"  also works..=20
>  =20
> So thankyou for the replies guys.=20
> I'll also look into the ABS function as suggested.=20
>  =20
> Cheers,=20
> Scott.