RE: FW: [Dev-C++] Win32 Shell API

[Per W. <pw...@ia...>]

p would have to be char* since it must be changed to point at different
locations. char p[] is a fixed array that can't be moved.

/Per W

On Tue, 17 May 2005, Guillermo Gutierrez wrote:

> 'p' would be a char* then? or a char p[]?
>
> -----Original Message-----
> From: Per Westermark [mailto:pw...@ia...]
> Sent: Tuesday, May 17, 2005 4:30 PM
> To: Guillermo Gutierrez
> Cc: dev...@li...
> Subject: RE: FW: [Dev-C++] Win32 Shell API
>
>
> That is your problem.
>
> You simply can not use strcat to concatenate a "\0" since it breaks at the
> \0 in the string.
>
> p = SrcPath;
> strcpy(p,LP4);
> p += strlen(p)+1; // skip # of inserted chars + the '\0';
> strcpy(p,SFA);
> p += strlen(p)+1; // "-
> strcpy(p,"");     // just writes the final '\0'
>
> And of course, you can not use std::cout to emit a char* or char[] that
> contains '\0' in the middle...
>
> /Per W