Re: [Dev-C++] calculating PI

[Rafael C. <cha...@un...>]

Noorez,

Just a suggestion to your algorithm in
order to not use an "if/else" statement.

 <snip>
 const double numerator = 4;
 double PI = 4;  // short, signed or unsigned invalid for PI.
 // The only modifier you can use is "long" with "double"
 // bool add = false;
 short int sign = 1; //set a variable to act as a sign
 cout << "Running..." << endl;
 for(double i = 3; i < 999999999; i+=2){
       sign *= -1; //switches the "sign" on each iteration
       PI += ((numerator/i)*sign);
 }
 </snip>

Regards,
Rafael Charnovscki

"Alfred P. Reaud" wrote:
> 
> Hi Noorez,
> 
> Is there such a thing as an unsigned double?  IMHO, floats and doubles
> ...................
> int main(int argc, char *argv[])
> {
>   const double numerator = 4;
>   double PI = 4;  // short, signed or unsigned invalid for PI.
>   bool add = false;
>   cout << "Running..." << endl;
>   for(double i = 3; i < 999999999; i+=2)
>   {
>     if( add )
>     {
>       PI += numerator/i;
>       add = false;
>     }
>     else
>     {
>       PI -= numerator/i;
>       add = true;
>     }
>   }
>   cout << setprecision(15) << PI << endl << endl;
>   system("PAUSE");
>   return EXIT_SUCCESS;
> }


-- 
No virus found in this outgoing message.
Checked by AVG Anti-Virus.
Version: 7.0.308 / Virus Database: 266.11.0 - Release Date: 29/04/05