Re: [Dev-C++] please help me to write formulas

[Verne H. B. <ve...@sy...>]

I haven't heard back from you but here's a simple Console type program =
that would do what you wish if it works as it works for me.  This could =
easily be made into a loop with if and while and such but does the trick =
as is right now.

********************************************
#include <cstdlib>
#include <iostream>

using namespace std;

int main(int argc, char *argv[])
{
   =20
    int height, width1,width2, area;
    cout << " Please give me the height then the width and \n"
    << " in inches then the area will be given to you.\n\n";
    cin >> height;
    cin >> width1 >> width2;
    cout << "\nThe area of this is "<< (height * (width1 + width2)) / =
144 << " square feet!\n";
    system("PAUSE");
    return EXIT_SUCCESS;
}
**************************************

Verne


  Hi

  I am new here (and still studying C++),

  I would love to know how to do make my program check out the type of =
the user input, to make it more clear, am trying to write geometric =
formulas ...... and it works by making the user enter his datas // =
height area width etc....and lets say am doing the square function (not =
a class because am practicing now functions and I would like to take my =
time before I use classes) and in square function lets say that there =
are these (formulas):

  area =3D height * width; // this is in case the MISSING variable =
(input) is the area
  height =3D area / width; // in case the MISSING input is the Height=20
  and so on

  remember please that the user must enter the data and if he wites x or =
y (height, width) then the formula that needed to find (any missing =
argument or a value of variable) takes the action to do that, but how to =
make the program check what type of the input if I HAVE TO declare a =
variable for output (cin >> float a; for example).

  I mean the user cant type x or y if the out put is float //which =
should be!=20
  please help me,=20
  and thank very much.

  ligeti_78



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