Re: [Dev-C++] A Question of & use

[Roger F. <ra...@ha...>]

Aloha from Honolulu,

Kiryl,
   My original email had this:
 >>    First: in "Effective C++", item 15, p. 65:
 >>         "operator= default version C& C::operator=(const C&);"
 >> The & follows the variable (?).

I assumed the "C" following "C & C::operator=(const "
was the variable--somehow it must have got lost on you.  I understand 
const is a type def.
My major concern was with line 8 (below)
 >>         8:       CAT (const CAT &);    // copy constructor

But as Per W. pointed out in his reply on 8/24/04 8:49PM :
 >   int my_function(int &);
 > _doesn't_ have the & last, since there is an "invisible" :) parameter 
name
 > following it. It is just a lazy short-form of declaration.

   That the var is invisible was the info I needed.
   Regarding "lhs" and "rhs", I was confused because "The Complete 
Reference C++" never seems to use them.  Perhaps he's keeping his code 
as simple as possible for clarity sake.  I continue to find his examples 
most useful in gaining an understanding of the language.  (My background 
was Pascal through the '80s and early '90s--in MSDOS).
My thanks for all your help, Per especially.
Mahalo,
Roger

Kiryl V Mauryshchau wrote:

> > "operator= default version C& C::operator=(const &);"
> > The & follows the variable (?).
>  
> Are you sure that it follows the variable. Maybe what you think is a 
> variable in fact is a type definition. Check it.
>  
> > 8:       CAT (const CAT &);   
>  
> Here, "const CAT" is type, not variable. When you _declare_ some 
> method, you can omit variable. Like in this case.
>
> > 27:      CAT::CAT(const CAT & rhs)
>
> Here, "const CAT" is type, and "rhs" is variable/object. As I 
> mentioned before, when you declare a function or method in the class 
> (.h file), you may omit the variable/object in declaration. But when 
> you write a function/method itself in implementation file, then you 
> specify this variable/object.
>  
> I am pretty sure, that in the first example above, what precedes the 
> ampersand is type.
>  
> Regards,