Re: [Dev-C++] program with no window or console

[Per W. <pw...@ia...>]

How about making it a Windows application, i.e. using WinMain() instead of
main() as entry point. Then you won't get a console window.

By the way, in case the copy fails, your program display both message
boxes, i.e. the OK box too.

Also, there is no need to have a system("PAUSE") at the end of the
program. The message box is enough.

/Per W

On Fri, 20 Aug 2004, Guillermo Gutierrez wrote:

> How would I get a program to run without displaying a console or a window?
> I just want it to do its thing and then pop up a message box with a message at the end.
>
> My program does what I want it to do, but I don't want a console or window to appear.
>
> Here is my code:
> _____________________________________________
> #include <iostream>
> #include <stdlib.h>
> #include <windows.h>
> #include <winbase.h>
>
> using namespace std;
>
> int main(int argc, char *argv[])
> {
>   char* cFileToCopy = "Q:\\QA\\2004-08 RC1\\lp4.exe";
>   char* cDestination = "C:\\Documents and Settings\\ggutierrez\\Desktop\\lp4.exe";
>
>   cout<<"gonna copy:\n";
>   cout<<"this   ->" << cFileToCopy<<endl;
>   cout<<"to this->" << cDestination<<endl;
>   system("PAUSE");
>
>   if (CopyFile(cFileToCopy, cDestination, false) == 0)
>   {
>       MessageBox(NULL, "File Copy Failed", "Error", MB_OK);
>   }
>   MessageBox(NULL, "Files Copied Successfully.", "Copy Complete",  MB_OK);
>
>   system("PAUSE");
>   return 0;
> }
>
> any suggestions?
>
> Guillermo Gutierrez
> Market Scan Information Systems
> Software Q.A. Supervisor
> (818) 575-2000 x2427
> ggu...@ma...
>
>