Re: [Dev-C++] array + pointers???

[<dan...@ya...>]

 --- Noorez Kassam <coo...@ho...>
escreveu: > I have asked questions about pointers and
arrays but

>    int nArray[5]={1,2,3,4,5};
>    cout << nArray << endl;/*this gives the address
> of the array*/

Yes, this is the default for pointers; if you use just
the name of the array, you get the address of the
begining of the array; so nArray acts just like a
pointer.


>    char sArray[6]={'h','e','l','l','o',\0};
>    cout << sArray << endl;/*this give the string
> hello, but i used the name 
> of the array without  subscripts? Don't i get the
> address of it like in the 
> int array?*/


No. The << operator for ostream's is overloaded to
handle pointers to char (char*) in a special way. If
you cast your sArray (when you're printing it) to
another type, like void*, you'll get the address. i
suggest you to start first with C, not with C++. Or
get yourself a good book (D&D, TC++PL and so on).



>    char* pszString = "hello";/*strangest of all*/

Isn't strange at all. You are declaring a C string
constant, and pointing pszString to it.



Daniel K. O.


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