RE: [Dev-C++] newbie function_struct_array problem

[Amit K. S. <ams...@qu...>]

Give the  correct type of the first parameter in following function.
 
void CreateEmployee (struct Emp[], int); //prototype
 
And you cann't pass the non const value to size of array.
 
thanks.
-amit

 

-----Original Message-----
From: dev...@li...
[mailto:dev...@li...]On Behalf Of Dane Ensign
Sent: Saturday, May 15, 2004 3:01 AM
To: dev...@li...
Subject: [Dev-C++] newbie function_struct_array problem


Hi,
Dane here. Im having trouble getting my assignment program to compile. There
is something incorrect between the 
function prototype, function call, and function headerline. But I cant
figure it out. Please can someone help me to understand
where I am going wrong?
 
Thank you in advance for any help you can offer me. Im sorry if Im not
supposed to include my code. SHould I attach it next time?
 
Here is my source:
______________________________________________
#include <iostream>
#include <stdlib.h>
#include <string.h>
using namespace std;
void CreateEmployee (struct [], int); //prototype
struct Emp
{
    char fname[20];
    char lname[20];
    int age, id;
};
 
int qty;
 


int main()
{
    cout << "How many Employees do you want?" << endl;
    cin >> qty;
    cout << "You chose to create " << qty << "employees" << endl;
  
  Emp Employee[qty];
  CreateEmployee(Employee, qty);
  //DisplayTeam(qty);
  
    cout << "Nice Job Chap! Peaceout";
 
  system("PAUSE"); 
  
  return 0;
}
 
void CreateEmployee(struct Employee[], int qty)
{
    int b, qtyLocal;
    qtyLocal = qty;
   for (b = 0; b < qtyLocal; b++)
    {
        Employee.id = 0;
        cout << "Employee Form" << endl;
        cout << "First name: " << endl;
        cin >> Employee[b].fname;
        cout << "Last name: " << endl;        
        cin >> Employee[b].lname;
        cout << "Age: " << endl;        
        cin >> Employee[b].age;
        cout << "Your Employee Summary is: " << endl; 
        cout << Employee[b].id << endl << Employee[b].fname << endl <<
Employee[b].lname << endl << Employee[b].age;         
              
    }
 
}
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