Re: [Dev-C++] Operator overloading for built in types.

[Abdelkader G. <go...@li...>]

hi there,

Are you sure that you can overload operator for simple types that are not 
classes? You can emulate built in types operators for you 
defined 'classes', but I'm not sure that you can redefine operator for 
built in types and if this is allowed what a catastrophy it would be ,) 
imagine this (bogus) code:

bool operator==(const int i,const int j)
{
 return (bool) (i + j);
}
//this code change the semantics of ==
// 4 == -4 -> true 4 == 4 ->false

If you are allowed to change the definition of the == (int equals) this 
means that this operator is changed for 'all' int == operation, so can you 
imagine what happends if you include others source code that have used 
another semantics for the (int ==).

So, I'm not sure that you can overload built in types but if you have more 
information I'm interested ,)

Kind regards;   

> Ok here is my dilema.
> 
> Scattered throught my code is the following line:
> 
> if(!strcmp(var1,var2))
> ....
> 
> What would be the best way to change that to
> 
> if( var1 == var2 )
> ....
> 
> So far here is some exaple code that illustrates my problem:
> bool operator==(char *s1, char *s2)
> {
>   if(!strcmp(s1,s2))
>     return true;
>   else
>     return false;
> }
> 
> int main()
> { 
>   char x[10] = "Hello";
>   char y[10] = "Hello";
>   if(x == y)
>     cout << "Equal" << endl;
>   else
>     cout << "Not equal" << endl;
>   cin.get();
>   return 0;
> }
> 
> Error:
> C:/Documents and Settings/David/My Documents/scratch.cpp:9: `bool 
>    operator==(char*, char*)' must have an argument of class or
> enumerated type
> 
> What does it mean?? I have done operator overloading with various
> classes but I can't get it to work with char *, please help. There is
> no one to make it a friend with so that is ruled out.
> 
> =====
> Signed 
> David Mcken
> 
> Life Sucks
> Live with it
> 
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