[Dev-C++] Converting macro to inline function.

[David M. <ci...@ya...>]

I am cleaing up some code and came across the following macro:

#define CREATE(result, type, number)  \
do  \
{  \
  if (!((result) = (type *) calloc ((number), sizeof(type)))) \
  { \
   perror("malloc failure");               \
   fprintf(stderr, "Malloc failure @ %s:%d\n", __FILE__, __LINE__ );
\
   abort();                        \
  }                               \
} while(0)

I want to convert to a function (most likely inline, its small
enough) the problme I am having is with the second parameter, it is a
data type!

So far the following seems like it would work:

template<class type>
inline void CREATE(result, number)
{
  if (!((result) = (type *) calloc ((number), sizeof(type))))
  {
   perror("malloc failure");
   fprintf(stderr, "Malloc failure @ %s:%d\n", __FILE__, __LINE__ );
   abort();
  } 
}

The problem is this macro is quite heavily used. Changing the
function to the following would require me to change the "macro call"
to the following function call:

CREATE<int>(pToSomewhere, 500); //To create 500 ints.

Is there around this or will I also have to change all the function
calls?

Thanks in Advance.
David McKen

P.S. I am lazy, I admit it. I don't want to change all those lines of
code, if I have to so be it. I am changing this macro to a function.

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