Re: [Dev-C++] How i convert a char matrix to int matrix ?

[Kevin W. <ke...@me...>]

Do not convert. Declare the matrix as an int array:

int main(int argc, char* argv[])
{
         int matrix[5][5] = {'0','0','0','0','0',
         '0','0','0','0','0',
         '0','0','0','0','0',
         '0','0','0','0','0',
         '0','0','0','0','0'};

         show_matrix(matrix);
         system("pause");
         return 0;
}

void show_matrix(int m[5][5])
{
         int i,j;

         for(i=0;i<5;i++)
         {
                 for(j=0;j<5;j++)
                 {
                         printf("%c ",m[i][j]);
                 }
                 printf("\n");
         }
}



Kev.
===========================

At 07:36 17/12/03, hu...@cl... wrote:
>char matrix[5][5] =
>{{'0','0','0','0','0'},
>{'0','0','0','0','0'},
>{'0','0','0','0','0'},
>{'0','0','0','0','0'},
>{'0','0','0','0','0'}
>};
>
>and i have this function :
>
>void show_matrix(int m[5][5))
>{
>int i,j;
>
>for(i=0;i<5;i++)
>{
>for(j=0;j<5;j++)
>{
>printf("%c ",m[i][j]);
>}
>printf("\n");
>}
>}