Re: [Dev-C++] Problems with arrays of pinters

[Per W. <pw...@ia...>]

Note that when you declare a text string as

char *str2 = "sldfksf"

str2 is only a pointer to a text. Most compilers will place the text in
read-only memory, i.e. if you try to follow the pointer to change the
text, you will get a memory access violation.

If you want to change a text you must use the array form of declaration.

/Per W

On Wed, 17 Sep 2003, Esteban Valverde wrote:

> Hi, the next code has an running error, non a compiler error. Anybody can
> understand it ?
>
> thanks, Esteban
>
>
> char str1[] = "Hello, how ";
> char *str2  = "are you ?";
>
> char *pstr[2];
>
> // these works fine...
> pstr[0] = str1;
> pstr[1] = str2;
>
> // these works fine...
> printf("%s%s\n", pstr[0], pstr[1]);
>
> // these works fine...
> if(*pstr[0] == 'H')
>   printf("\"%s\" start with 'H'\n", pstr[0]);
>
> if(*pstr[1] != 'x')
>   printf("\"%s\" don't start with 'X'\n", pstr[1]);
>
> // I'm attempting to increment 'H' to 'I'.
> // these works fine...
> (*pstr[0])++;
> printf("%s\n", pstr[0]);
>
> // I'm attempting to increment 'a' to 'b'.
> // these, doesn't works fine...
> // these halts the computer... the same with (*(pstr[1]))++
> (*pstr[1])++;
> printf("%s\n", pstr[1]);
>
>
>
>
>
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