RE: [Dev-C++] Weirdness with sprintf

[Ed C. <em...@to...>]

Oops...

First off, my pseudo-code below was off (I just KNEW I would do that...) =
- a
and b should have been declared as char *a, *b, as Reid pointed out. =
More
importantly, in my real code, I had accidentally declared char foo[1],
thinking I had declared foo[10]. No good.

Sorry about that.

-Ed


-----Original Message-----
From: Reid Thompson [mailto:rei...@at...]=20
Sent: Tuesday, September 09, 2003 8:31 PM
To: Ed Cottrell
Subject: Re: [Dev-C++] Weirdness with sprintf


change char a and char b to char *a and char *b and see what you get. =20
Looks like you are assigning a string to a single char variable  and =20
overflowing the allocated memory location. ie char a is a one char field =

and you are assigning a 5 char variabel to it and thus not 'getting' and =

end of string.

char *a =3D "Hello", *b =3D "World";
char c[20];

Ed Cottrell wrote:

> Hi -
>
> When I run the following code:
>      =20
>         char a =3D "Hello",
>                 b =3D "World",
>                 c[20];
>         sprintf(c, "%s %s", a, b);
>
> I expect c to contain "Hello World", but it contains "HelloWorld=20
> HelloWorld". In other words, it replaces EACH of the %s types in=20
> sprintf with a AND b.
>
> What's up with that? I'm doing almost exactly the same thing,=20
> elsewhere, with multiple arguments of the same type, and I'm not=20
> having problems there... Anybody who can help, I'd be much obliged!
>
> -Ed
>
>
>
>
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