Re: [Dev-C++] numerical error in a simple program

[Luís B. <lf...@ya...>]

--- Neszt Tibor <ne...@ss...> wrote:
> Instead of:
> 
> >   printf( " a = %15.15f\n", a );
> 
> Try:
>     printf( " a = %15.10f\n", a );
> 
> :-)
> 
> Tibor
> 

It's not a question of output. Numerically the error is still there:

*********************************
printf( "(int)a = %d\n", (int)a);
*********************************
output -> 3332



=====
+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=
Luís Filipe Delgado Brás
Eng.º Civil
Porto - Portugal
email: lf...@ya...
http://www.fotopt.net/autor.asp?autor=2637
+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=

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