Re: [Dev-C++] "no class template named " error

[Hossein H. <ult...@em...>]

Hi Gary,

> > My first suspection is that you are probabely getting that error because
> of
> > the following name:
> >
> > random_access_iterator_parent, that is here:
> >
> > >   class iterator
> > >    : public random_access_iterator_parent(seqref<T>)
> >
> > It is not a portable name. (I know it's probabely a template!) If you are
> > using a newer version of MSVC, it is likely that this new version doesn't
> use
> > that name as the parent of its iterators of type RandomAccess. Cehck it!

I checked it, and couldn't find any base for the RandomAccess
type. It could be nicer if the other members can check it as well.
(After all, 2 or more pairs of eyes are better than just 1.)
Assuming that beeing the case, the best way to get rid of that
error message, seems to replace that random_access_iterator_parent
with __normal_iterator. (If the "seqref" type is really needed.
Check it! If it not, then simply remove all of the:
": public random_access_iterator_parent(seqref)"

Even then, if you are going to stick to seqref, use it in one of
these forms:

> > >    : public random_access_iterator_parent(seqref<T>())
> >
> > or
> >
> > >    : public random_access_iterator_parent<seqref<T> > //The space is
> needed

Sorry if it is not so clear, I'm in a hurry!

Regards,
--Hossein
-- 
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