RE: [Dev-C++] %d and %ld printf output formats

[Ioannis V. <iv...@em...>]

> -----Original Message-----
> From: dev...@li...=20
> [mailto:dev...@li...] On Behalf=20
> Of Andr? Macario Barros
> Sent: Tuesday, August 26, 2003 6:30 AM
> To: Dev-Cpp-Users
> Subject: [Dev-C++] %d and %ld printf output formats
>=20
>=20
> Dear users,
>=20
> Please consider the following C code:
>=20
> ...
>    int var=3D65534;
>=20
> 1-   printf("%d\n", var);
> 2-   var++;
> 3-   printf("%d\n", var);
> 4-   var*=3D1000;
> 5-   printf("%d\n", var);
> 6-   var++;
> 7-   printf("%d\n", var);
> ...
>=20
> I though that above 65535 (or 32767!) I would need the %ld=20
> output format,
> but It wasn=B4t necessary.



%d specifies that the argument is of type int. The limits of type int =
are
implementation-specific. In this case you printf() the value of var =
which is
an int, so %ld shouldn't be used.



> Even in lines 5 and 7. I though the 2 complement would start=20
> presenting the
> complement values.


?


>=20
> Does anybody can explain what happend?


What was expected to happen. You printf() the stored values in decimal
format.






Ioannis Vranos
=20
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