RE: [Dev-C++] Code for all combinations

[Per W. <pw...@ia...>]

A slightly more efficient solution for the suspected  school assignment:

#define BASE 11
#define MAX_DIGITS 6

int digit,vec[MAX_DIGITS];
for (;;) {
    // This loop is also easy to unroll...
    for (digit =3D 0; digit < MAX_DIGITS; digit++) {
        if (++vec[digit] < BASE) break;
        vec[digit] =3D 0;
    }
    if (digit >=3D MAX_DIGITS) break;
    print(xx);
}

/Per W

On Wed, 23 Jul 2003, Rafael del Valle Huerta wrote:

> It's like counting in base 11 (6 digits, in reverse order).
>
> #define MAX 11L*11L*11L*11L*11L*11L  // 11^6 -> 1.7e6
> ...
> unsigned long n, m;
> int i;
> int vect[6]=3D{0};
> ...
> for(n=3D0; n<MAX; n++) {
>   m=3Dn;
>   for(i=3D5; i>=3D0; i--) {
>      vect[i]=3Dm%11;
>      m/=3D11;
>      printf("%ul, ", vect[i]);
>   }
>   printf("\n");
> }
> ...
>
> It's easy to "unroll" the inner loop in 6 steps and leave only one loop.
>
>
>
> -----Mensaje original-----
> De: dev...@li...
> [mailto:dev...@li...]En nombre de Rodolfo
> Dettorre
> Enviado el: mi=E9rcoles 23 de julio de 2003 6:31
> Para: Andr=E9 Mac=E1rio Barros; Dev-Cpp-Users
> Asunto: RE: [Dev-C++] Code for all combinations
>
>
> Hi,
>
> just curiosity, is that a school assignment?  An idea would be to nest si=
x
> for statements.
>
> Regards
>
> Rodolfo d'Ettorre
>
> -----Original Message-----
> From: Andr=E9 Mac=E1rio Barros [mailto:and...@su...]
> Sent: Wednesday, 23 July 2003 1:54 PM
> To: Dev-Cpp-Users
> Subject: [Dev-C++] Code for all combinations
>
>
> Dear Users,
>
>    I need to test all possibilities in a specific code.
>    I couldn=B4t realize how I can generate theese possibilities with two
> for=B4s.
>    Here is the problem:
>
>    Suppose you have a vector like
>    int vect[6]=3D{0};
>
>    How could be a C code to have (print for example) all possible
> combinations in the
> six positions from the range 0 to 10?
> the output is something like:
>    0 , 0, 0, 0, 0, 0
>    1 , 0, 0, 0, 0, 0
>    2 , 0, 0, 0, 0, 0
>    ...
>    10, 0, 0, 0, 0, 0
>    0 , 1, 0, 0, 0, 0
>    0 , 2, 0, 0, 0, 0
>    ...
>    0 ,10, 0, 0, 0, 0
>    1,  1, 0, 0, 0, 0
>    2,  1, 0, 0, 0, 0
>    ...
>    10, 1, 0, 0, 0, 0
>    1 , 2, 0, 0, 0, 0
>    2 , 2, 0, 0, 0, 0
>    ...
>    10, 2, 0, 0, 0, 0
>    ...
>    ...
>    10,10,10,10,10,10
>
>    Some repetition values are allowed, that is, if you have to
> reset all values to begin the counting to another digit, etc.
>
> Regards
> Andre
>
>
>
>
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