RE: [Dev-C++] Code for all combinations

[Rafael d. V. H. <rde...@in...>]

It's like counting in base 11 (6 digits, in reverse order).

#define MAX 11L*11L*11L*11L*11L*11L  // 11^6 -> 1.7e6
...
unsigned long n, m;
int i;
int vect[6]={0};
...
for(n=0; n<MAX; n++) {
  m=n;
  for(i=5; i>=0; i--) {
     vect[i]=m%11;
     m/=11;
     printf("%ul, ", vect[i]);
  }
  printf("\n");
}
...

It's easy to "unroll" the inner loop in 6 steps and leave only one loop.



-----Mensaje original-----
De: dev...@li...
[mailto:dev...@li...]En nombre de Rodolfo
Dettorre
Enviado el: miércoles 23 de julio de 2003 6:31
Para: André Macário Barros; Dev-Cpp-Users
Asunto: RE: [Dev-C++] Code for all combinations


Hi,

just curiosity, is that a school assignment?  An idea would be to nest six
for statements.

Regards

Rodolfo d'Ettorre

-----Original Message-----
From: André Macário Barros [mailto:and...@su...]
Sent: Wednesday, 23 July 2003 1:54 PM
To: Dev-Cpp-Users
Subject: [Dev-C++] Code for all combinations


Dear Users,

   I need to test all possibilities in a specific code.
   I couldn´t realize how I can generate theese possibilities with two
for´s.
   Here is the problem:

   Suppose you have a vector like
   int vect[6]={0};

   How could be a C code to have (print for example) all possible
combinations in the
six positions from the range 0 to 10?
the output is something like:
   0 , 0, 0, 0, 0, 0
   1 , 0, 0, 0, 0, 0
   2 , 0, 0, 0, 0, 0
   ...
   10, 0, 0, 0, 0, 0
   0 , 1, 0, 0, 0, 0
   0 , 2, 0, 0, 0, 0
   ...
   0 ,10, 0, 0, 0, 0
   1,  1, 0, 0, 0, 0
   2,  1, 0, 0, 0, 0
   ...
   10, 1, 0, 0, 0, 0
   1 , 2, 0, 0, 0, 0
   2 , 2, 0, 0, 0, 0
   ...
   10, 2, 0, 0, 0, 0
   ...
   ...
   10,10,10,10,10,10

   Some repetition values are allowed, that is, if you have to
reset all values to begin the counting to another digit, etc.

Regards
Andre




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