Re: [Dev-C++] overloading delete

[Per W. <pw...@ia...>]

The void* parameter of delete is only guaranteed in linear addressing
mode. For 16-bit segmented code, delete might take a couple of other
parameter types, depending on memory model used.

It might take void __near* and void __far *.

The void __far * is for 16-bit Intel composed of a 16:16 bit pointer,
where the first 16 bit are the segment, and the next 16 bit are offset.

However, a 16:16 pointer is still treated as a single parameter in the
code, i.e. you still write "delete myobj;", where myobj contains a pointer
returned by new.

It is just code performing advanced pointer manipulation that needs to
know that the pointer is segmented. For memory areas < 64kB this isn't
a problem since the offset part spans 64kB. Arrays and memory blocks
larger than 64kB do require special treatment, such as conversion to void
__huge * to make sure that the offset part is always normalized 0..15 and
the segment is constantly adjusted too.

/Per W

On Tue, 15 Jul 2003, Hossein Haeri wrote:

> Dear Daniel,
>
> > What parameters does delete take? I'm being told by the compiler the first
> > is __segment and the second is a __based(void)*   ?????
> > Is this right?
>
> If you only want the arguments, the following (the full signature) will
> convince you:
>
> void* operator delete(void*) throw();
> void* operator delete [] (void*) throw();
>
> I cite them directly from the Standard draft. But if you need more
> information take a look to Section 3.7.3.2 (Deallocation functions) in
> Standard. I don't have Accrobat Distiller. If I had I would send you
> the wholl chapter as a pdf file.
>
> You will also find good stuff in TC++PL:Spec. E.g., consider Section
> 6.2.6.2, Section 15.6.1, and (the best at) Section 19.4.5.
>
> Regards,
> --Hossein
>
>
> --
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