Fw: [Dev-C++] Question about pointers (beginner)

[Felipe L. <li...@cp...>]

When you say *ptr = &variable, you are assigning the memory address of the
variable to the pointer, not the variable's real value(123).
So the final value of ptr_int would be the memory address of the
variable(x), which is unknown for us, only the program knows.


-=-=-=-=-=-=-
Felipe Lima - Software Tester/ Developer
CPTS - Software Test Research Center
HP Brazil  - PUCRS
----- Original Message -----
From: "Christian Schmidt" <sm...@xs...>
To: <dev...@li...>
Sent: Tuesday, May 27, 2003 3:17 PM
Subject: [Dev-C++] Question about pointers (beginner)


> >From my book:
>
> Given x = 123 and ptr_int = &x after that *ptr_int = 456 has been
executed.
> What is the value of x?
>
> I thought it was 123 as the pointer *ptr_int is a null pointer and can't
> have any value.
>
> This is how I see it:
>
> main ( )
> {
> int x, *ptr_int;
>
> *ptr_int = 456; /*This pointer is a null pointer at this moment right? */
>
> x =123;
> ptr_int = &x; /* As x is just set to 123 and the statement *ptr_int = 456;
> was executed before I would think *ptr_int would be 123 */
>
> }
>
> ----------
>
> But the books says the value of *ptr_int at the end is 456. How come??
>
> Thanks for your time,
>
> Christian
>
>
>
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