Re: [Dev-C++] Error while doing a simple example

[Per W. <pw...@ia...>]

The example code assumed 16-bit integers, but our beloved gcc port is
using 32-bit integers.

Change your declarations to:
  short x;
  unsigned short y;
and test again.

/Per W

On Tue, 20 May 2003, Christian Schmidt wrote:

> Hi,
>
> >From the book learn C in 24 hours I typed this lesson and build/run it:
>
> #include <stdio.h>
>
> main ( )
>
> {
>
>   int x;
>   unsigned int y;
>   x = 0xAB78;
>   y = 0xAB78u;
>
>   printf ("De decimal value of 0xAB78 is: %d.\n", x);
>   printf ("De decimal value of 0xAB78u is: %u.\n", y);
>
>   return 0;
>
> }
>
> However this returns me for both statments (printf's):  43896 but the book
> tells me it should return -21640 for the signed integer (first printf).
>
> I'm using:
>
> Windows 2000 SP3
> PIII 550 MHz
> DevC++ 4.9.8.0
>
> Could anyone tell where my mistake is?
>
> Thanks in advance.
>
>
>
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