[Dev-C++] itoa() with no sprintf()

[Ioannis V. <iv...@em...>]

I decided to take the subject a bit more seriuosly and ended with the
following:


#include <stdlib.h>
#include <stdio.h>

char *iitoa(int i)
{
 long Length, j;
 char *p;
 
 char numchars[]="0123456789";

 int temp=i;

 int sign=temp<0?-1:1;
 
 if(!temp)
 {
 	p=malloc(2);
 	
 	if(!p)
 	  return NULL;
 	  
 	p[0]='0', p[1]=0;

   return p;
 }
 
 for(Length=1; temp/=10; Length++)
    ;
    
 p=malloc(Length+=1+(sign==-1));
 
 if(!p)
   return NULL;

 if(sign==-1)
   p[0]='-';

 p[Length-1]=0;


 for(temp=i*sign, j=Length-2; j>=(sign==1?0:1); j--)
 {
    p[j]=numchars[temp%10];
    temp/=10;
 }


 return p;
}


It doesn't convert to any other number base, it produces only in decimal.


My apologies for the many emails.




Ioannis Vranos
 
* Programming pages: http://www.noicys.freeurl.com
* Alternative URL: http://run.to/noicys