Re: [Dev-C++] integer to string

[Per W. <pw...@ia...>]

Assign of string termination will be one position off, i.e. outside your
buffer.

A buffer[MAXSZ] may only access from 0 to MAXSZ-1 and the pointer is
initialized to p[MAXSZ], i.e. first index outside the buffer.

/Per W

On Tue, 1 Apr 2003, Luigi Santillo wrote:

> Hello,
>
> I've revised the previous implementation of "itoa", adding the
> enhancements that Per Westmark suggested. The code lacks error
> checking, so isn't robust at all.
>
> --
> >> gisan >>
>
>
>
> t_itoa.c
> --------
> #include <stdio.h>
> #include "itoa.h"
>
> int
> main()
> {
>   int k = 123;       /* integer value to be converted */
>   char *s = itoa(k); /* string holding the converted value */
>
>   printf("INPUT:\tk = %d\n", k);
>   printf("OUTPUT:\ts = %s\n\n", s);
>
>   k = -4567; /* a little harder: using a negative number */
>   s = itoa(k);
>   printf("INPUT:\tk = %d\n", k);
>   printf("OUTPUT:\ts = %s\n\n", s);
>
>   return 0;
> }
> --------
>
>
> itoa.h
> ------
> #ifndef itoa_h
> #define itoa_h
> #pragma defs_in itoa.c  /* needed by makefile generator (ignore it) */
>
> /* turn an integer into a string (i.e. an array) */
> char *
> itoa(int n);
>
> #endif /* not itoa_h */
> ------
>
>
> itoa.c
> ------
> #include "itoa.h"
> #define MAXSZ   21  /* assuming integer is made of 19 digits + sign */
>
> char *
> itoa(int n)
> {
>   static char buf[MAXSZ];
>   char *p = buf + MAXSZ; /* sweep across buffer */
>   char neg = 0;  /* 1 means that the integer is negative */
>
>   if (n < 0) /* negative integer */
>     {
>       n = -n;  /* work on its absolute value */
>       neg = 1; /* turn on the flag */
>     }
>
>   *p = '\0'; /* terminate string */
>
>   while (n && p > buf)  /* main loop */
>     {
>       *--p = '0' + n % 10; /* char for a digit as offset from '0' */
>       n /= 10; /* drop last character */
>     }
>
>   if (neg && p > buf ) /* prepend a negative sign */
>     *--p = '-';
>
>   return p;
> }
> ------
>
>
>
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