[Dev-C++] Re: Dev-cpp-users digest, Vol 1 #1223 - 11 msgs

[Dave R. <eb...@eq...>]

Hi There

The code you posted fils because B() member function is undefined so change
this:

#include <set>
template <class T>
class A
{
    public:
        A();
        B();
        std::set<T> _list;
};

to this

#include <set>
template <class T>
class A
{
    public:
        A();
        void B();
        std::set<T> _list;
};



and it should work fine. In C++ class definitions only constructors and
destructors have no return type. In your case member A() is the constructor
for class A ( becuase of its name ), and member B() is an "ordinary" member
and _needs_ to have a type declared.


Hope this helps

Regards

Dave



> Message: 11
> From: "erwan ancel" <erw...@fr...>
> To: <dev...@li...>
> Date: Sun, 12 Jan 2003 11:26:01 +0100
> Subject: [Dev-C++] templates in C++ : precisions
>
> well, this is my problem:
>
> I would like to make a template class that owns a set of elements that
have
> the type of one of the class parameters. And it doesn't compile...
> example:
>
> #include <set>
> template <class T>
> class A
> {
>     public:
>         A();
>         B();
>         std::set<T> _list;
> };
>
> the compiler's output tells that the type T is not defined... Well, of
> course, but it will be defined when the template will be instanciated. So
it
> should be possible...
> Does anybody know a solution to my problem?
>
>
>
>
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