Re: [Dev-C++] address 0x33313031 out of bounds

[Per W. <pw...@ia...>]

Only, only, only use strcpy when you KNOW that your receiving buffer is
big enough. Are you sure that argv[1] only contains 2 characters? If not,
the copy to type will use unallocated stack space. As soon as you call
func(), the end of the string will be lost.

/Per W

On Thu, 12 Dec 2002 ma...@mm... wrote:

> i'm having a bit of a problem. i get to a particular line in my program and
> i crashes no matter how i try and get it to work. the relevant code
> basically goes.....
> 
> void func (char *type)
> {
>      char key[10];
> 
>      printf("type is currently %s", type);
> 
>      sprintf(key, "last%s", type); //crashes at this point
>      printf("key is currently %s", key);
> }
> 
> int main (int argc, char *argv[])
> {
>      char type[3];
>      strcpy(type,argv[1]);
>      func(type);
> }
> 
> if i watch type, after it crashes it tells me that address 0x33313031 is
> out of bounds. i can't see that i'm doing anything wrong. what does the
> error actually mean?
> 
> thanx in advance
> 
> 
> 
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